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List the dimensions of each variable.

Computer Science

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  1. List the dimensions of each variable.

    • Time period TT: [T][T]
    • Mass mm: [M][M]
    • Force FF: [M][L][T]−2[M][L][T]^{-2} (since force = mass ×\times acceleration)
    • Distance xx: [L][L]
    • The constant 2π2\pi is dimensionless.
  2. Determine the dimensions of the Left Hand Side (LHS).

    The LHS is TT, so its dimension is [T][T].

  3. Determine the dimensions of the Right Hand Side (RHS).

    The RHS is 2πmFx2\pi \sqrt{\frac{m}{Fx}}. We only need to consider the dimensions of the terms under the square root.
    Dimensions of mFx\frac{m}{Fx}:

    [M]([M][L][T]−2)×[L]=[M][M][L]2[T]−2=[L]−2[T]2\frac{[M]}{([M][L][T]^{-2}) \times [L]} = \frac{[M]}{[M][L]^2[T]^{-2}} = [L]^{-2}[T]^2

    Now, take the square root of this expression:

    [L]−2[T]2=([L]−2[T]2)1/2=[L]−1[T]\sqrt{[L]^{-2}[T]^2} = ([L]^{-2}[T]^2)^{1/2} = [L]^{-1}[T]

    So, the dimension of the RHS is [L]−1[T][L]^{-1}[T].

  4. Compare the dimensions of LHS and RHS.

    LHS dimension: [T][T]
    RHS dimension: [L]−1[T][L]^{-1}[T]
    Since [T]≠[L]−1[T][T] \neq [L]^{-1}[T], the formula is dimensionally incorrect.

    The formula T=2πmFxT = 2\pi \sqrt{\frac{m}{Fx}} is dimensionally incorrect.

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