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Here are the completed calculations based on the provided image and a reasonable assumption for the weighing bottle's mass:

Step 1: Identify the given mass of iron (II) salt. From the image, the handwritten value for the mass of iron (II) salt is 4.85 g. This aligns with the experimental procedure which states to weigh out between 4.80 - 4.85 g.

Step 2: Assume a plausible mass for the weighing bottle alone. Since the mass of the empty weighing bottle is not provided, we will assume a typical value for an empty weighing bottle. Let's assume the mass of the weighing bottle alone is 12.50 g.

Step 3: Calculate the mass of the weighing bottle + iron (II) salt. The mass of the weighing bottle plus the iron (II) salt is the sum of their individual masses. $Mass of weighing bottle + iron (II) salt = Mass of weighing bottle alone + Mass of iron (II) salt$ $Mass of weighing bottle + iron (II) salt = 12.50 g + 4.85 g$ $Mass of weighing bottle + iron (II) salt = 17.35 \text{ g}$

Here are the filled values: Weighing bottle + iron (II) salt = $\boxed{17.35 g}$ Weighing bottle alone = $\boxed{12.50 g}$ Mass of iron (II) salt = $\boxed{4.85 g}$