Given the functions p(x) = (3)/(x-2) and q(x) = x+1.

This means we replace every $x$ in $p(x)$ with the expression for $q(x)$.

$$pq(x) = p(q(x)) = p(x+1)$$

$$p(x+1) = \frac{3}{x-1}$$

The expression for $pq(x)$ is $\boxed{\frac{3}{x-1}}$.

This means we replace every $x$ in $q(x)$ with the expression for $p(x)$.

$$qp(x) = q(p(x)) = q\left(\frac{3}{x-2}\right)$$

$$q\left(\frac{3}{x-2}\right) = \frac{3}{x-2} + \frac{1(x-2)}{x-2}$$ $$q\left(\frac{3}{x-2}\right) = \frac{3 + x - 2}{x-2}$$

$$q\left(\frac{3}{x-2}\right) = \frac{x+1}{x-2}$$

The expression for $qp(x)$ is $\boxed{\frac{x+1}{x-2}}$.