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Given theta = (3)/(5).

Mathematics

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Answer

120\frac{1}{20}

Step-by-step solution

5 steps
  1. Find the value of sin⁡θ\sin \theta.

    Given cos⁡θ=35\cos \theta = \frac{3}{5}.
    Using the Pythagorean identity sin⁡2θ+cos⁡2θ=1\sin^2 \theta + \cos^2 \theta = 1:

    sin⁡2θ+(35)2=1\sin^2 \theta + \left(\frac{3}{5}\right)^2 = 1 sin⁡2θ+925=1\sin^2 \theta + \frac{9}{25} = 1 sin⁡2θ=1−925\sin^2 \theta = 1 - \frac{9}{25} sin⁡2θ=2525−925\sin^2 \theta = \frac{25}{25} - \frac{9}{25} sin⁡2θ=1625\sin^2 \theta = \frac{16}{25}

    Taking the square root, we get:

    sin⁡θ=±1625=±45\sin \theta = \pm \sqrt{\frac{16}{25}} = \pm \frac{4}{5}

    Assuming θ\theta is an acute angle (in the first quadrant), sin⁡θ\sin \theta is positive.

    sin⁡θ=45\sin \theta = \frac{4}{5}
  2. Simplify tan⁡(90∘−θ)\tan(90^\circ - \theta).

    Using the complementary angle identity, tan⁡(90∘−θ)=cot⁡θ\tan(90^\circ - \theta) = \cot \theta.

  3. Find the value of cot⁡θ\cot \theta.

    We know that cot⁡θ=cos⁡θsin⁡θ\cot \theta = \frac{\cos \theta}{\sin \theta}.
    Substitute the values of cos⁡θ\cos \theta and sin⁡θ\sin \theta:

    cot⁡θ=3545=34\cot \theta = \frac{\frac{3}{5}}{\frac{4}{5}} = \frac{3}{4}
  4. Substitute the values into the expression sin⁡θ−tan⁡(90∘−θ)\sin \theta - \tan(90^\circ - \theta).

    The expression becomes:

    sin⁡θ−cot⁡θ\sin \theta - \cot \theta

    Substitute the values found in Step 1 and Step 3:

    45−34\frac{4}{5} - \frac{3}{4}
  5. Calculate the final value.

    To subtract the fractions, find a common denominator, which is 20:

    4×45×4−3×54×5\frac{4 \times 4}{5 \times 4} - \frac{3 \times 5}{4 \times 5} 1620−1520\frac{16}{20} - \frac{15}{20} 16−1520\frac{16 - 15}{20} 120\frac{1}{20}
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