לפניכם מנסרות ישרות שבסיסן משולשים שוויי-צלעות שאינם ישרים זוויות. האורכים הם בס"מ. היעזרו בנתון לגבי גובה הבסיס AB, וחשו את שטח הפנים של כל מנסרה:
|Mathematics
לפניכם מנסרות ישרות שבסיסן משולשים שוויי-צלעות שאינם ישרים זוויות. האורכים הם בס"מ. היעזרו בנתון לגבי גובה הבסיס AB, וחשו את שטח הפנים של כל מנסרה:
ScanSolve AI Answer
Answer
*(107+674)cm2≈158.61cm2∗
א.
Step 1: Calculate the area of the base triangle.
The diagram for part a shows a right-angled triangle with legs 5 cm and 7 cm. We will proceed with this interpretation, assuming the general description "isosceles triangles that are not right-angled" does not apply to this specific diagram. The height of the prism is AB=6 cm.
Abase=21×leg1×leg2=21×5cm×7cm=17.5cm2
Step 2: Calculate the perimeter of the base triangle.
First, find the hypotenuse c using the Pythagorean theorem.
c=52+72=25+49=74 cmPbase=5cm+7cm+74cm=(12+74) cm
Step 3: Calculate the total surface area of the prism.
The height of the prism is hprism=AB=6 cm. The total surface area is Atotal=2×Abase+Pbase×hprism.
Atotal=2×17.5cm2+(12+74)cm×6 cmAtotal=35cm2+(72+674)cm2Atotal=(107+674)cm2
Using 74≈8.6023:
Atotal≈107+6×8.6023cm2≈107+51.6138cm2≈158.61cm2
The total surface area for prism a is ∗(107+674)cm2≈158.61cm2∗.
ב.
Step 1: Calculate the area of the base triangle.
The base is an isosceles triangle with sides 13 cm, 13 cm, and 10 cm. The height of the prism is AB=12 cm.
To find the height of the triangle (hbase), we bisect the base of 10 cm into two 5 cm segments.
hbase2+52=132hbase2+25=169hbase2=144hbase=12 cmAbase=21×base×hbase=21×10cm×12cm=60cm2
Step 2: Calculate the perimeter of the base triangle.
Pbase=13cm+13cm+10cm=36 cm
Step 3: Calculate the total surface area of the prism.
The height of the prism is hprism=AB=12 cm.
Atotal=2×Abase+Pbase×hprismAtotal=2×60cm2+36cm×12 cmAtotal=120cm2+432cm2Atotal=552cm2
The total surface area for prism b is ∗552cm2∗.
ג.
Step 1: Calculate the area of the base triangle.
The base is an isosceles triangle with sides 26 cm, 26 cm, and 20 cm. The height of the prism is AB=24 cm.
To find the height of the triangle (hbase), we bisect the base of 20 cm into two 10 cm segments.
hbase2+102=262hbase2+100=676hbase2=576hbase=24 cmAbase=21×base×hbase=21×20cm×24cm=240cm2
Step 2: Calculate the perimeter of the base triangle.
Pbase=26cm+26cm+20cm=72 cm
Step 3: Calculate the total surface area of the prism.
The height of the prism is hprism=AB=24 cm.
Atotal=2×Abase+Pbase×hprismAtotal=2×240cm2+72cm×24 cmAtotal=480cm2+1728cm2Atotal=2208cm2
The total surface area for prism c is ∗2208cm2∗.
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This mathematics problem involves applying core mathematical principles and formulas. Below you will find a complete step-by-step solution with detailed explanations for each step, helping you understand not just the answer but the method behind it.
ScanSolve AI Answer
א. Step 1: Calculate the area of the base triangle. The diagram for part a shows a right-angled triangle with legs 5 cm and 7 cm. We will proceed with this interpretation, assuming the general description "isosceles triangles that are not right-angled" does not apply to this specific diagram. The height of the prism is AB = 6 cm. A_base = (1)/(2) × leg_1 × leg_2 = (1)/(2) × 5 cm × 7 cm = 17.5 cm^2 Step 2: Calculate the perimeter of the base triangle. First, find the hypotenuse c using the Pythagorean theorem. c = sqrt(5^2 + 7^2) = sqrt(25 + 49) = sqrt(74) cm P_base = 5 cm + 7 cm + sqrt(74) cm = (12 + sqrt(74)) cm Step 3: Calculate the total surface area of the prism. The height of the prism is h_prism = AB = 6 cm. The total surface area is A_total = 2 × A_base + P_base × h_prism. A_total = 2 × 17.5 cm^2 + (12 + sqrt(74)) cm × 6 cm A_total = 35 cm^2 + (72 + 6sqrt(74)) cm^2 A_total = (107 + 6sqrt(74)) cm^2 Using sqrt(74) ≈ 8.6023: A_total ≈ 107 + 6 × 8.6023 cm^2 ≈ 107 + 51.6138 cm^2 ≈ 158.61 cm^2 The total surface area for prism a is (107 + 6sqrt(74)) cm^2 ≈ 158.61 cm^2 . ב. Step 1: Calculate the area of the base triangle. The base is an isosceles triangle with sides 13 cm, 13 cm, and 10 cm. The height of the prism is AB = 12 cm. To find the height of the triangle (h_base), we bisect the base of 10 cm into two 5 cm segments. h_base^2 + 5^2 = 13^2 h_base^2 + 25 = 169 h_base^2 = 144 h_base = 12 cm A_base = (1)/(2) × base × h_base = (1)/(2) × 10 cm × 12 cm = 60 cm^2 Step 2: Calculate the perimeter of the base triangle. P_base = 13 cm + 13 cm + 10 cm = 36 cm Step 3: Calculate the total surface area of the prism. The height of the prism is h_prism = AB = 12 cm. A_total = 2 × A_base + P_base × h_prism A_total = 2 × 60 cm^2 + 36 cm × 12 cm A_total = 120 cm^2 + 432 cm^2 A_total = 552 cm^2 The total surface area for prism b is 552 cm^2 . ג. Step 1: Calculate the area of the base triangle. The base is an isosceles triangle with sides 26 cm, 26 cm, and 20 cm. The height of the prism is AB = 24 cm. To find the height of the triangle (h_base), we bisect the base of 20 cm into two 10 cm segments. h_base^2 + 10^2 = 26^2 h_base^2 + 100 = 676 h_base^2 = 576 h_base = 24 cm A_base = (1)/(2) × base × h_base = (1)/(2) × 20 cm × 24 cm = 240 cm^2 Step 2: Calculate the perimeter of the base triangle. P_base = 26 cm + 26 cm + 20 cm = 72 cm Step 3: Calculate the total surface area of the prism. The height of the prism is h_prism = AB = 24 cm. A_total = 2 × A_base + P_base × h_prism A_total = 2 × 240 cm^2 + 72 cm × 24 cm A_total = 480 cm^2 + 1728 cm^2 A_total = 2208 cm^2 The total surface area for prism c is 2208 cm^2 . That's 2 down. 3 left today — send the next one.