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Analyze the provided pedigree chart: identify diagram type, count females, count affected F1 males, and determine Kate's genotype.

Biology

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Question 3.1.1

  1. Identify the type of diagram.

    The diagram illustrates the inheritance pattern of a genetic trait across multiple generations within a family.

    • The type of diagram shown is a pedigree chart.

    Question 3.1.2

  2. Count all individuals represented by circles in the pedigree chart.

    • Generation I: 2 females (Kate and her sister)
    • Generation II: 2 females (Helen and her sister)
    • Generation III: 2 females (daughters of Helen and Ben)
    • There are a total of 6 females in this family.

    Question 3.1.3

  3. Identify the F1-generation and count affected males.

    The F1-generation consists of the children of the initial parents (Steve and Kate), which is the second row of individuals. Males are represented by squares, and affected individuals are shaded.

    • In the F1-generation, there are two males. One is Ben (unaffected, unshaded). The other is Ben's brother (affected, shaded).
    • 1 male in the F1-generation has Goltz syndrome.

    Question 3.1.4

  4. Determine Kate's genotype based on the given information and the pedigree.

    Goltz syndrome is a sex-linked dominant disorder (allele XG^{G}). Unaffected individuals have the recessive allele Xg^{g}.

    • Kate is an affected female (shaded circle).
    • Kate's father, Steve, is an unaffected male (unshaded square), so his genotype is Xg^{g}Y.
    • Since Kate inherited an X chromosome from her father, she must have inherited Xg^{g} from Steve.
    • As Kate is affected, she must also possess the dominant allele XG^{G}.
    • Therefore, Kate's genotype is XGXg\boxed{\text{X}^{G}\text{X}^{g}}.

    Question 3.1.5

  5. Determine the genotypes of Helen and Ben.

    • Helen is an unaffected female (unshaded circle). Since Goltz syndrome is dominant, an unaffected female must be homozygous recessive: Xg^{g}Xg^{g}.
    • Ben is an unaffected male (unshaded square). His genotype is Xg^{g}Y.
  6. Determine the possible genotypes of their sons.

    Sons inherit an X chromosome from their mother and a Y chromosome from their father.

    • Helen (Xg^{g}Xg^{g}) can only pass an Xg^{g} chromosome to her sons.
    • Ben (Xg^{g}Y) passes a Y chromosome to his sons.
    • Therefore, all sons will have the genotype Xg^{g}Y.
  7. State the phenotype of their sons.

    • A genotype of Xg^{g}Y means the individual does not have the dominant allele for Goltz syndrome.
    • The phenotype of their sons will be unaffected.
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