Formulate a 15% crude protein (CP) ration for a goat using maize (8% CP) and soybean meal (44% CP) using the Pearson Square Method. Show all workings and calculate the daily feed requirements.

Biology

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Answer

×0.8056=0.8056 kg or 805.6 g\times 0.8056 = 0.8056 \text{ kg} \text{ or } 805.6 \text{ g}

×0.1944=0.1944 kg or 194.4 g\times 0.1944 = 0.1944 \text{ kg} \text{ or } 194.4 \text{ g}

Step-by-step solution

4 steps

let's formulate this ration.

  1. Set up the Pearson Square

    Place the target crude protein (CP) percentage in the center of the square. Place the CP percentages of the two ingredients at the left corners.

    Soybean Meal (44% CP)15−8=7 parts Maize╲15% CP (Target)╱Maize (8% CP)44−15=29 parts Soybean Meal\begin{array}{c c c} \text{Soybean Meal (44\% CP)} & & 15 - 8 = 7 \text{ parts Maize} \\ & \diagdown & \\ & 15\% \text{ CP (Target)} & \\ & \diagup & \\ \text{Maize (8\% CP)} & & 44 - 15 = 29 \text{ parts Soybean Meal} \\ \end{array}
  2. Calculate the parts of each ingredient

    Subtract diagonally across the square. The absolute difference represents the "parts" of the ingredient on the opposite side.

    • Parts of Soybean Meal needed: 44%−15%=2944\% - 15\% = 29 parts
    • Parts of Maize needed: 15%−8%=715\% - 8\% = 7 parts
  3. Calculate the total parts and percentage of each ingredient

    Total parts = 29 (Soybean Meal)+7 (Maize)=3629 \text{ (Soybean Meal)} + 7 \text{ (Maize)} = 36 parts

    Percentage of Soybean Meal:

    29 parts36 total parts×100%=80.56%\frac{29 \text{ parts}}{36 \text{ total parts}} \times 100\% = 80.56\%

    Percentage of Maize:

    7 parts36 total parts×100%=19.44%\frac{7 \text{ parts}}{36 \text{ total parts}} \times 100\% = 19.44\%
  4. Calculate daily feed requirements

    To calculate daily feed requirements, we need to assume a typical daily dry matter intake for a goat.
    Let's assume a goat weighs 40 kg40 \text{ kg} and consumes 2.5%2.5\% of its body weight in dry matter per day.

    Daily Dry Matter Intake:

    40 kg×0.025=1 kg or 1000 g40 \text{ kg} \times 0.025 = 1 \text{ kg} \text{ or } 1000 \text{ g}

    Daily requirement for Soybean Meal:

    1 kg×0.8056=0.8056 kg or 805.6 g1 \text{ kg} \times 0.8056 = \boxed{0.8056 \text{ kg} \text{ or } 805.6 \text{ g}}

    Daily requirement for Maize:

    1 kg×0.1944=0.1944 kg or 194.4 g1 \text{ kg} \times 0.1944 = \boxed{0.1944 \text{ kg} \text{ or } 194.4 \text{ g}}
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