Given that the frequency of color blind females is 1 in 25000, calculate the expected frequency of female carriers using the Hardy-Weinberg principle.

Step 1: Understand the genetic basis of color blindness. Color blindness is an X-linked recessive trait. For females, the genotypes are X^C X^C (normal vision), X^C X^c (carrier), and X^c X^c (color blind). According to the Hardy-Weinberg principle, if p is the frequency of the dominant allele (X^C) and q is the frequency of the recessive allele (X^c), then the frequency of color blind females (X^c X^c) is q^2. Step 2: Calculate the frequency of the recessive allele (q). The frequency of color blind females is given as 1 in 25000. q^2 = (1)/(25000) To find q, take the square root of q^2: q = sqrt((1)/(25000)) q = (1)/(sqrt(25000)) q = (1)/(50sqrt(10)) q ≈ (1)/(50 × 3.16227766) q ≈ (1)/(158.113883) q ≈ 0.006324555 Step 3: Calculate the frequency of the dominant allele (p). Using the Hardy-Weinberg equation p + q = 1: p = 1 - q p = 1 - 0.006324555 p = 0.993675445 Step 4: Calculate the frequency of female carriers. Female carriers have the genotype X^C X^c. Their frequency in the population is given by 2pq. 2pq = 2 × 0.993675445 × 0.006324555 2pq ≈ 2 × 0.00628455 2pq ≈ 0.0125691 Rounding to five decimal places, the expected frequency of carriers is 0.01257. The expected frequency of the carriers of this allele in the population is approximately 0.01257. Send me the next one 📸