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State the Hardy-Weinberg principle and explain its assumptions. What are the implications of homozygosity and heterozygosity?

Biology

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Here are the solutions to questions 4 and 5.

QUESTION 4

a) State the Hardy-Weinberg principle and explain the underlying assumptions. (04 marks)

The Hardy-Weinberg principle states that in a large, randomly mating population, the allele and genotype frequencies will remain constant from generation to generation, provided that no evolutionary influences are acting upon it.

The underlying assumptions for the Hardy-Weinberg equilibrium are:

  1. No mutation: No new alleles are created, and existing alleles do not change.
  2. No gene flow (migration): There is no movement of individuals or gametes into or out of the population.
  3. Random mating: Individuals mate without regard to their genotypes.
  4. No genetic drift: The population is large enough to prevent random fluctuations in allele frequencies.
  5. No natural selection: All genotypes have equal survival and reproductive rates.

b) What are the implications of homozygosity and heterozygosity in a population? (04 marks)

Homozygosity (having two identical alleles for a gene) can lead to the expression of recessive traits, which can be either beneficial or detrimental. Increased homozygosity, often due to inbreeding, can expose deleterious recessive alleles, potentially reducing fitness or increasing susceptibility to genetic disorders.

Heterozygosity (having two different alleles for a gene) provides genetic variation within a population, which is crucial for adaptation to changing environments. Heterozygotes can also mask the expression of harmful recessive alleles, and in some cases, heterozygotes may have a selective advantage (heterozygote advantage), such as resistance to certain diseases.

c) In Mirabilis jalapa plants, the flower color exhibits incomplete dominance inheritance. During a genetic experiment involving these plants, a total of 1,000 plants in F1 were obtained in a segregation ratio of 250 white-flowers, 450 with pink flowers, and 300 red-flowers. Calculate the:

Total plants = 1000
White flowers = 250
Pink flowers = 450
Red flowers = 300

Let R be the allele for red color and W be the allele for white color.
Genotypes: Red = RR, Pink = RW, White = WW.

i. Phenotypic frequencies in the population (04 marks)

  1. Calculate the frequency for each phenotype.

    Frequency of White=Number of WhiteTotal plants=2501000=0.25\text{Frequency of White} = \frac{\text{Number of White}}{\text{Total plants}} = \frac{250}{1000} = 0.25 Frequency of Pink=Number of PinkTotal plants=4501000=0.45\text{Frequency of Pink} = \frac{\text{Number of Pink}}{\text{Total plants}} = \frac{450}{1000} = 0.45 Frequency of Red=Number of RedTotal plants=3001000=0.30\text{Frequency of Red} = \frac{\text{Number of Red}}{\text{Total plants}} = \frac{300}{1000} = 0.30

    The phenotypic frequencies are:

    • White: 0.25\boxed{\text{0.25}}
    • Pink: 0.45\boxed{\text{0.45}}
    • Red: 0.30\boxed{\text{0.30}}

    ii. Allele frequencies in the population (04 marks)

  2. Calculate the total number of alleles.

    Total alleles = 2×Total plants=2×1000=20002 \times \text{Total plants} = 2 \times 1000 = 2000

  3. Calculate the number of R alleles.

    Number of R alleles = (2×Number of Red)+(1×Number of Pink)(2 \times \text{Number of Red}) + (1 \times \text{Number of Pink})
    Number of R alleles = (2×300)+(1×450)=600+450=1050(2 \times 300) + (1 \times 450) = 600 + 450 = 1050

  4. Calculate the frequency of allele R (pp).

    p=Number of R allelesTotal alleles=10502000=0.525p = \frac{\text{Number of R alleles}}{\text{Total alleles}} = \frac{1050}{2000} = 0.525
  5. Calculate the number of W alleles.

    Number of W alleles = (2×Number of White)+(1×Number of Pink)(2 \times \text{Number of White}) + (1 \times \text{Number of Pink})
    Number of W alleles = (2×250)+(1×450)=500+450=950(2 \times 250) + (1 \times 450) = 500 + 450 = 950

  6. Calculate the frequency of allele W (qq).

    q=Number of W allelesTotal alleles=9502000=0.475q = \frac{\text{Number of W alleles}}{\text{Total alleles}} = \frac{950}{2000} = 0.475

    The allele frequencies are:

    • Frequency of R (pp): 0.525\boxed{\text{0.525}}
    • Frequency of W (qq): 0.475\boxed{\text{0.475}}

    iii. Genotypic frequencies in the population (04 marks)

  7. Calculate the frequency for each genotype.

    Frequency of RR=Number of RedTotal plants=3001000=0.30\text{Frequency of RR} = \frac{\text{Number of Red}}{\text{Total plants}} = \frac{300}{1000} = 0.30 Frequency of RW=Number of PinkTotal plants=4501000=0.45\text{Frequency of RW} = \frac{\text{Number of Pink}}{\text{Total plants}} = \frac{450}{1000} = 0.45 Frequency of WW=Number of WhiteTotal plants=2501000=0.25\text{Frequency of WW} = \frac{\text{Number of White}}{\text{Total plants}} = \frac{250}{1000} = 0.25

    The genotypic frequencies are:

    • Frequency of RR: 0.30\boxed{\text{0.30}}
    • Frequency of RW: 0.45\boxed{\text{0.45}}
    • Frequency of WW: 0.25\boxed{\text{0.25}}

    QUESTION 5

    a) State the multiple gene hypothesis. (04 marks)

    The multiple gene hypothesis, also known as polygenic inheritance, states that many genes, each contributing a small, additive effect, determine a single phenotypic trait. This interaction of multiple genes often results in continuous variation of the trait within a population, rather than discrete categories.

    b) What characteristics distinguish quantitative traits from qualitative traits. (08 marks)

    Qualitative traits are characteristics that fall into distinct categories and are typically controlled by one or a few genes, with minimal environmental influence. Examples include blood type (A, B, AB, O) or flower color (red, white).

    Quantitative traits are characteristics that show continuous variation across a range, often measured on a scale, and are influenced by multiple genes (polygenic inheritance) as well as significant environmental factors. Examples include human height, weight, or crop yield.

    c) Besides, quantitative inheritance, discuss four non-Mendelian inheritance patterns. (08 marks)

    1. Incomplete Dominance: In this pattern, the heterozygous phenotype is an intermediate blend of the two homozygous phenotypes. For example, a cross between a red-flowered plant and a white-flowered plant might produce pink-flowered offspring.
    2. Codominance: Both alleles in a heterozygote are fully and distinctly expressed, without blending. A classic example is the ABO blood group system in humans, where individuals with AB blood type express both A and B antigens on their red blood cells.
    3. Multiple Alleles: This occurs when there are more than two possible alleles for a single gene within a population. While an individual can only carry two alleles, the population gene pool contains several variants. The ABO blood group system is also an example of multiple alleles (Iᴬ, Iᴮ, i).
    4. Epistasis: This is a phenomenon where the expression of one gene is affected (masked or modified) by one or more other genes at different loci. For instance, in Labrador retrievers, one gene determines coat color (black or brown), but another gene determines whether the color is deposited in the fur at all, leading to yellow labs regardless of the first gene's alleles.
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