To solve this problem, we will use the Hardy-Weinberg principle, which describes the genetic equilibrium in a randomly mating population. Let: $p$ = frequency of the dominant allele (A, normal pigmentation) $q$ = frequency of the recessive allele (a, albinism) The Hardy-Weinberg equations are: 1. Allele frequencies: $p + q = 1$ 2. Genotype frequencies: $p^2 + 2pq + q^2 = 1$ • $p^2$ represents the frequency of homozygous dominant individuals (AA). • $2pq$ represents the frequency of heterozygous individuals (Aa, carriers). • $q^2$ represents the frequency of homozygous recessive individuals (aa, individuals with albinism). Given information: Total population (N) = 10,000 individuals Number of individuals with albinism (recessive trait, aa) = 1,600 Step 1: Calculate the frequency of the homozygous recessive genotype ($q^2$). The frequency of individuals with albinism is the number of affected individuals divided by the total population. $$q^2 = \frac{\text{Number of individuals with albinism}}{\text{Total population}}$$ $$q^2 = \frac{1600}{10000}$$ $$q^2 = 0.16$$ Step 2: Calculate the frequency of the recessive allele ($q$). Take the square root of $q^2$. $$q = \sqrt{0.16}$$ $$q = 0.4$$ Step 3: Calculate the frequency of the dominant allele ($p$). Using the allele frequency equation $p + q = 1$: $$p = 1 - q$$ $$p = 1 - 0.4$$ $$p = 0.6$$ Step 4: Calculate the frequency of carriers ($2pq$). Carriers are heterozygous individuals (Aa). $$2pq = 2 \times p \times q$$ $$2pq = 2 \times 0.6 \times 0.4$$ $$2pq = 2 \times 0.24$$ $$2pq = 0.48$$ Step 5: Calculate the number of carriers in the population. Multiply the frequency of carriers by the total population. $$\text{Number of carriers} = 2pq \times \text{Total population}$$ $$\text{Number of carriers} = 0.48 \times 10000$$ $$\text{Number of carriers} = 4800$$ The number of individuals in this population who are "CARRIERS" of the albino allele is 4,800. Comparing this to the given options: A) 8,400 B) 4,800 C) 3,600 D) 480 The correct option is B. The final answer is $\boxed{\text{B) 4,800}}$.