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p = frequency of the dominant allele (A, normal pigmentation)

Biology

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Answer

B

Step-by-step solution

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To solve this problem, we will use the Hardy-Weinberg principle, which describes the genetic equilibrium in a randomly mating population.

Let:
pp = frequency of the dominant allele (A, normal pigmentation)
qq = frequency of the recessive allele (a, albinism)

The Hardy-Weinberg equations are:

  1. Allele frequencies: p+q=1p + q = 1
  2. Genotype frequencies: p2+2pq+q2=1p^2 + 2pq + q^2 = 1
    • p2p^2 represents the frequency of homozygous dominant individuals (AA).
    • 2pq2pq represents the frequency of heterozygous individuals (Aa, carriers).
    • q2q^2 represents the frequency of homozygous recessive individuals (aa, individuals with albinism).

Given information:
Total population (N) = 10,000 individuals
Number of individuals with albinism (recessive trait, aa) = 1,600

  1. Calculate the frequency of the homozygous recessive genotype (q2q^2).

    The frequency of individuals with albinism is the number of affected individuals divided by the total population.

    q2=Number of individuals with albinismTotal populationq^2 = \frac{\text{Number of individuals with albinism}}{\text{Total population}} q2=160010000q^2 = \frac{1600}{10000} q2=0.16q^2 = 0.16
  2. Calculate the frequency of the recessive allele (qq).

    Take the square root of q2q^2.

    q=0.16q = \sqrt{0.16} q=0.4q = 0.4
  3. Calculate the frequency of the dominant allele (pp).

    Using the allele frequency equation p+q=1p + q = 1:

    p=1−qp = 1 - q p=1−0.4p = 1 - 0.4 p=0.6p = 0.6
  4. Calculate the frequency of carriers ($2pq$).

    Carriers are heterozygous individuals (Aa).

    2pq=2×p×q2pq = 2 \times p \times q 2pq=2×0.6×0.42pq = 2 \times 0.6 \times 0.4 2pq=2×0.242pq = 2 \times 0.24 2pq=0.482pq = 0.48
  5. Calculate the number of carriers in the population.

    Multiply the frequency of carriers by the total population.

    Number of carriers=2pq×Total population\text{Number of carriers} = 2pq \times \text{Total population} Number of carriers=0.48×10000\text{Number of carriers} = 0.48 \times 10000 Number of carriers=4800\text{Number of carriers} = 4800

    The number of individuals in this population who are "CARRIERS" of the albino allele is 4,800.

    Comparing this to the given options:
    A) 8,400
    B) 4,800
    C) 3,600
    D) 480

    The correct option is B.

    The final answer is B) 4,800\boxed{\text{B) 4,800}}.

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