An electric immersion heater is inserted to a calorimeter made up of copper of mass 15kg and a current of 0.1A a voltage of 1.6V was passed through the meter and a water if mass 40kg was put in a calorimeter at a temperature of 30°C provided by the metre then a piece of ice of mass 2kg is added at a temperature of -2°C into the metre and stirred continuously until it reaches the final temperature.if the process takes 15mins find the final temperature of the mixture assuming negligible heat loss S.h.c of water=4200J/kg/k L.h.c of ice=336000J/kg S.h.c of copper=400J/kg/k

Fresh day Gu, let's solve. To find the final temperature of the mixture, we will use the principle of conservation of energy, stating that the heat lost by the warmer components (copper calorimeter and initial water) plus the heat supplied by the electric heater equals the heat gained by the colder component (ice) to melt and then warm up. First, we list the given values and make an assumption for the specific heat capacity of ice. Mass of copper calorimeter, m_Cu = 15 kg Specific heat capacity of copper, c_Cu = 400 J/kg/K Initial temperature of copper, $T_Cu,i = 30^