Hey Omar, good to see you again.
Q1.
a)
Step 1: Let the total marks be T. We are given that 45 marks represent 60% of the total marks.
0.60×T=45
Step 2: Divide both sides by 0.60 to find T.
T=0.6045
T=75
The total marks are 75.
b)
Step 1: Calculate 80% of the total marks.
80%of75=0.80×75=60
Step 2: Find the difference between 80% of the total marks and the student's current score.
Marks needed=60−45=15
The student needs 15 more marks to reach 80%.
Q2.
Step 1: Find the total number of ratio parts.
Total ratio parts=2+3+4=9
Step 2: Find the value of one ratio part.
Value per part=9GH₵360=GH₵40
a)
Step 3: Calculate Kofi's share.
Kofi’s share=2×GH₵40=GH₵80
Kofi's share is GH₵80.
b)
Step 4: Calculate Ama's share.
Ama’s share=3×GH₵40=GH₵120
Ama's share is GH₵120.
c)
Step 5: Calculate Yaw's share.
Yaw’s share=4×GH₵40=GH₵160
Yaw's share is GH₵160.
Q3.
Given: Length (L) = 20 m, Width (W) = 15 m.
a)
Step 1: Use the formula for the perimeter of a rectangle.
P=2(L+W)
P=2(20m+15m)
P=2(35m)
P=70 m
The perimeter is 70 m.
b)
Step 1: Use the formula for the area of a rectangle.
A=L×W
A=20m×15 m
A=300m2
The area is 300 m2.
c)
Step 1: Calculate the cost of fencing using the perimeter and the cost per metre.
Cost=Perimeter×Cost per metre
Cost=70m×GH₵5/m
Cost=GH₵350
The cost of fencing is GH₵350.
Q4.
Given: Two angles on a straight line are (x+10)∘ and (3x−20)∘.
a)
Step 1: Angles on a straight line sum to 180∘.
(x+10)+(3x−20)=180
Step 2: Combine like terms.
4x−10=180
Step 3: Add 10 to both sides.
4x=190
Step 4: Divide by 4.
x=4190
x=47.5
The value of x is 47.5.
b)
Step 1: Calculate the values of the two angles using x=47.5.
First angle=(x+10)∘=(47.5+10)∘=57.5∘
Second angle=(3x−20)∘=(3×47.5−20)∘=(142.5−20)∘=122.5∘
Step 2: Assume "that angle" refers to the first angle, 57.5∘. The sum of angles in a triangle is 180∘.
Third angle=180∘−50∘−57.5∘
Third angle=130∘−57.5∘
Third angle=72.5∘
The third angle is 72.5∘.
Q5.
a)
Step 1: Let the original price be P. A 10% discount means the selling price is 90% of the original price.
0.90×P=GH₵180
Step 2: Divide by 0.90 to find P.
P=0.90GH₵180
P=GH₵200
The original price was GH₵200.
b)
Step 1: Calculate the profit.
Profit=SellingPrice−Cost Price
Profit=GH₵540−GH₵450=GH₵90
Step 2: Calculate the profit percentage.
Profit Percentage=CostPriceProfit×100%
Profit Percentage=GH₵450GH₵90×100%
Profit Percentage=0.2×100%
Profit Percentage=20%
The profit percentage is 20%.
Q6.
Given marks: 42, 55, 50, 48, 55, 62, 38, 50, 55, 60, 45, 48.
i.
Step 1: Identify the frequency of each mark.
• 38: 1
• 42: 1
• 45: 1
• 48: 2
• 50: 2
• 55: 3
• 60: 1
• 62: 1
The mark that appears most frequently is 55.
The mode is 55.
ii.
Step 1: Identify the highest and lowest marks.
Highest mark = 62
Lowest mark = 38
Step 2: Calculate the range.
Range=Highestmark−Lowest mark
Range=62−38=24
The range is 24.
b)
Given: 4 red, 3 blue, 3 green balls.
Step 1: Calculate the total number of balls.
Total balls=4+3+3=10
i.
Step 2: Calculate the probability of drawing a blue ball.
P(Blue)=TotalnumberofballsNumberofblueballs
P(Blue)=103
The probability of drawing a blue ball is 103.
ii.
Step 3: Calculate the probability of drawing a ball that is not green.
Number of non-green balls=Numberofredballs+Number of blue balls
Number of non-green balls=4+3=7
P(Notgreen)=TotalnumberofballsNumberofnon−greenballs
P(Notgreen)=107
The probability of drawing a ball that is not green is 107.
Q7.
a)
Step 1: Identify the fixed fee and the cost per kilometer.
Fixed fee = GH₵10
Cost per km = GH₵1.20
Distance = 15 km
Step 2: Calculate the total cost.
Total cost=Fixedfee+(Costperkm×Distance)
Total cost=GH₵10+(GH₵1.20/km×15km)
Total cost=GH₵10+GH₵18
Total cost=GH₵28
A passenger will pay GH₵28 for a trip of 15 km.
b)
Given: Length (L) = 85 m, Width (W) = 60 m.
i.
Step 1: Use the formula for the perimeter of a rectangle.
P=2(L+W)
P=2(85m+60m)
P=2(145m)
P=290 m
The perimeter of the field is 290 m.
ii.
Step 1: The fencing around the field is its perimeter.
Perimeter fencing=290 m
Step 2: To divide the field into 5 equal smaller plots by lines parallel to the shorter side (60 m), 4 internal fences are needed.
Number of internal fences=5−1=4
Step 3: Each internal fence will have the length of the shorter side.
Length of each internal fence=60 m
Step 4: Calculate the total length of internal fencing.
Total internal fencing=4×60m=240 m
Step 5: Calculate the total fencing needed.
Total fencing=Perimeterfencing+Total internal fencing
Total fencing=290m+240m=530 m
A total of 530 m of