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A) The chemical reaction is anaerobic respiration (fermentation) of glucose by yeast.

Chemistry

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  1. a) The chemical reaction is anaerobic respiration (fermentation) of glucose by yeast.
C6H12O6⟶2C2H5OH+2CO2\text{C}_6\text{H}_{12}\text{O}_6 \longrightarrow 2\text{C}_2\text{H}_5\text{OH} + 2\text{CO}_2

b) One economic importance is the production of alcoholic beverages (e.g., beer, wine) or baking (e.g., bread making, where CO2\text{CO}_2 causes dough to rise).

c) To verify the identity of the gas produced, bubble the gas through limewater (calcium hydroxide solution). If the gas is carbon dioxide, the limewater will turn cloudy or milky.

  1. a) It is difficult to calculate the respiratory quotient (RQ) in plants because plants also perform photosynthesis, which consumes carbon dioxide and produces oxygen. This interferes with the accurate measurement of the net carbon dioxide produced and oxygen consumed solely by respiration.

b) i) Balance the equation:

  1. Balance carbon atoms.

    There are 16 carbon atoms on the left, so place a coefficient of 16 in front of CO2\text{CO}_2.

    C16H32O2+O2⟶H2O+16CO2+Energy\text{C}_{16}\text{H}_{32}\text{O}_2 + \text{O}_2 \longrightarrow \text{H}_2\text{O} + 16\text{CO}_2 + \text{Energy}
  2. Balance hydrogen atoms.

    There are 32 hydrogen atoms on the left, so place a coefficient of 16 in front of H2O\text{H}_2\text{O} (16×2=3216 \times 2 = 32).

    C16H32O2+O2⟶16H2O+16CO2+Energy\text{C}_{16}\text{H}_{32}\text{O}_2 + \text{O}_2 \longrightarrow 16\text{H}_2\text{O} + 16\text{CO}_2 + \text{Energy}
  3. Balance oxygen atoms.

    Count oxygen atoms on the right side: 16 O from H2O+(16×2) O from CO2=16+32=48 O atoms16 \text{ O from } \text{H}_2\text{O} + (16 \times 2) \text{ O from } \text{CO}_2 = 16 + 32 = 48 \text{ O atoms}.
    Count oxygen atoms on the left side: 2 O from C16H32O2\text{C}_{16}\text{H}_{32}\text{O}_2.
    We need 48−2=46 O atoms48 - 2 = 46 \text{ O atoms} from O2\text{O}_2. Since O2\text{O}_2 has 2 oxygen atoms, we need 462=23 O2\frac{46}{2} = 23 \text{ O}_2 molecules.
    The balanced equation is:

    C16H32O2+23O2⟶16H2O+16CO2+Energy\boxed{\text{C}_{16}\text{H}_{32}\text{O}_2 + 23\text{O}_2 \longrightarrow 16\text{H}_2\text{O} + 16\text{CO}_2 + \text{Energy}}
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