Solid E reacts with dilute hydrochloric acid to produce Solution F and a colourless gas G. Solution F is…

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Solid E reacts with dilute hydrochloric acid to produce Solution F and a colourless gas G. Solution F is later shown to contain copper(II) ions. If Solid E is copper(II) carbonate, it reacts with hydr

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Hapa kuna majibu ya maswali yako: I) Step 1: Solid E reacts with dilute hydrochloric acid to produce Solution F and a colourless gas G. Solution F is later shown to contain copper(II) ions. If Solid E is copper(II) carbonate, it reacts with hydrochloric acid to form copper(II) chloride (Solution F), water, and carbon dioxide gas (colourless gas G). CuCO₃(s) + 2HCl(aq) → CuCl₂(aq) + H₂O(l) + CO₂(g) Therefore, solid E is copper(II) carbonate. Solid E: Copper(II) carbonate II) Step 2: From the reaction in Step 1, the colourless gas G produced is carbon dioxide. Gas G: Carbon dioxide III) Step 3: Solution H is the deep blue solution formed when the blue precipitate (copper(II) hydroxide) reacts with excess aqueous ammonia. This deep blue solution contains the tetraamminecopper(II) complex ion. Cu(OH)₂(s) + 4NH₃(aq) → [Cu(NH₃)₄]²⁺(aq) + 2OH⁻(aq) The formula of the compound (ion) in solution H is [Cu(NH₃)₄]²⁺. Formula of the compound in solution H: [Cu(NH₃)₄]²⁺ IV) Step 4: The reaction in Step II involves Solution F (containing Cu²⁺(aq) ions) reacting with 3 drops of aqueous ammonia to form a blue precipitate, which is copper(II) hydroxide, Cu(OH)₂(s). Aqueous ammonia provides hydroxide ions. Ionic equation for the reaction in Step II: Cu²⁺(aq) + 2NH₃(aq) + 2H₂O(l) → Cu(OH)₂(s) + 2NH₄⁺(aq)

Solid E reacts with dilute hydrochloric acid to produce Solution F and a colourless gas G. Solution F is later shown to contain copper(II) ions. If Solid E is copper(II) carbonate, it reacts with hydr

Step-by-step solution

Solid E reacts with dilute hydrochloric acid to produce Solution F and a colourless gas G.

From the reaction in Step 1, the colourless gas G produced is carbon dioxide.

Solution H is the deep blue solution formed when the blue precipitate (copper(II) hydroxide) reacts with excess aqueous ammonia.

The reaction in Step II involves Solution F (containing $\text{Cu}^{2+}\text{(aq)}$ ions) reacting with 3 drops of aqueous ammonia to form a blue precipitate, which is copper(II) hydroxide, $\text{Cu(OH)}_2\text{(s)}$ .

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Solid E reacts with dilute hydrochloric acid to produce Solution F and a colourless gas G. Solution F is later shown to contain copper(II) ions. If Solid E is copper(II) carbonate, it reacts with hydr

Step-by-step solution

Solid E reacts with dilute hydrochloric acid to produce Solution F and a colourless gas G.

From the reaction in Step 1, the colourless gas G produced is carbon dioxide.

Solution H is the deep blue solution formed when the blue precipitate (copper(II) hydroxide) reacts with excess aqueous ammonia.

The reaction in Step II involves Solution F (containing Cu2+(aq)\text{Cu}^{2+}\text{(aq)}Cu2+(aq) ions) reacting with 3 drops of aqueous ammonia to form a blue precipitate, which is copper(II) hydroxide, Cu(OH)2(s)\text{Cu(OH)}_2\text{(s)}Cu(OH)2​(s).

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The reaction in Step II involves Solution F (containing $\text{Cu}^{2+}\text{(aq)}$ ions) reacting with 3 drops of aqueous ammonia to form a blue precipitate, which is copper(II) hydroxide, $\text{Cu(OH)}_2\text{(s)}$ .