Which time interval has the fastest reaction

Chemistry

ScanSolve AI Answer

Answer

first minute\text{first minute}

Step-by-step solution

3 steps

To determine which time interval has the fastest reaction, we need to calculate the rate of reaction for each 1-minute interval by finding the change in the volume of carbon dioxide produced during that minute.

  1. Read the volume of CO2\text{CO}_2 at each minute mark from the graph.

    • At t=0t=0 min, Volume = 0 mL0 \text{ mL}
    • At t=1t=1 min, Volume = 9 mL9 \text{ mL}
    • At t=2t=2 min, Volume = 16 mL16 \text{ mL}
    • At t=3t=3 min, Volume = 21 mL21 \text{ mL}
    • At t=4t=4 min, Volume = 24 mL24 \text{ mL}
    • At t=5t=5 min, Volume = 26 mL26 \text{ mL}
  2. Calculate the rate of reaction for each 1-minute interval.

    • First minute (0-1 min): Rate=Volume at 1 min−Volume at 0 min1 min=9 mL−0 mL1 min=9 mL/min\text{Rate} = \frac{\text{Volume at } 1 \text{ min} - \text{Volume at } 0 \text{ min}}{1 \text{ min}} = \frac{9 \text{ mL} - 0 \text{ mL}}{1 \text{ min}} = 9 \text{ mL/min}
    • Second minute (1-2 min): Rate=Volume at 2 min−Volume at 1 min1 min=16 mL−9 mL1 min=7 mL/min\text{Rate} = \frac{\text{Volume at } 2 \text{ min} - \text{Volume at } 1 \text{ min}}{1 \text{ min}} = \frac{16 \text{ mL} - 9 \text{ mL}}{1 \text{ min}} = 7 \text{ mL/min}
    • Third minute (2-3 min): Rate=Volume at 3 min−Volume at 2 min1 min=21 mL−16 mL1 min=5 mL/min\text{Rate} = \frac{\text{Volume at } 3 \text{ min} - \text{Volume at } 2 \text{ min}}{1 \text{ min}} = \frac{21 \text{ mL} - 16 \text{ mL}}{1 \text{ min}} = 5 \text{ mL/min}
    • Fourth minute (3-4 min): Rate=Volume at 4 min−Volume at 3 min1 min=24 mL−21 mL1 min=3 mL/min\text{Rate} = \frac{\text{Volume at } 4 \text{ min} - \text{Volume at } 3 \text{ min}}{1 \text{ min}} = \frac{24 \text{ mL} - 21 \text{ mL}}{1 \text{ min}} = 3 \text{ mL/min}
    • Fifth minute (4-5 min): Rate=Volume at 5 min−Volume at 4 min1 min=26 mL−24 mL1 min=2 mL/min\text{Rate} = \frac{\text{Volume at } 5 \text{ min} - \text{Volume at } 4 \text{ min}}{1 \text{ min}} = \frac{26 \text{ mL} - 24 \text{ mL}}{1 \text{ min}} = 2 \text{ mL/min}
  3. Compare the rates to find the fastest reaction.

    The rates are:

    • First minute: 9 mL/min9 \text{ mL/min}
    • Second minute: 7 mL/min7 \text{ mL/min}
    • Third minute: 5 mL/min5 \text{ mL/min}
    • Fourth minute: 3 mL/min3 \text{ mL/min}
    • Fifth minute: 2 mL/min2 \text{ mL/min}

    The fastest reaction rate is 9 mL/min9 \text{ mL/min}, which occurs in the first minute.

    The time interval with the fastest reaction is the first minute\text{first minute}.

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