Step 1: Answer Question 1(a) - Name the substances in the Solvay process.
- a)
- (i) Solution A: Brine (concentrated sodium chloride solution)
- (ii) Substance B: Ammoniated brine
- (iii) Solid S: Sodium hydrogen carbonate (NaHCO3β)
Step 2: Answer Question 1(b) - Write equations for reactions in Chamber 2 and Chamber 3.
- b)
- (i) Chamber 2: Recovery of ammonia.
2NH4βCl(aq)+Ca(OH)2β(aq)βCaCl2β(aq)+2NH3β(g)+2H2βO(l)
- (ii) Chamber 3: Formation of sodium hydrogen carbonate.
NaCl(aq)+NH3β(g)+H2βO(l)+CO2β(g)βNaHCO3β(s)+NH4βCl(aq)
Step 3: Answer Question 1(c) - Identify processes (i) and (ii).
- c)
- (i) Process (I): Carbonation or Precipitation (formation of sodium hydrogen carbonate)
- (ii) Process (II): Thermal decomposition or Calcination (conversion of sodium hydrogen carbonate to sodium carbonate)
Step 4: Answer Question 1(d) - Explain how carbon(IV) oxide is obtained.
- d) Carbon(IV) oxide (CO2β) is obtained by the thermal decomposition of limestone (CaCO3β) in a lime kiln:
CaCO3β(s)βCaO(s)+CO2β(g)
It can also be obtained by burning coke (carbon):
C(s)+O2β(g)βCO2β(g)
Step 5: Answer Question 1(e) - Give two reasons for the efficiency of the Solvay process.
- e)
- Most of the raw materials, such as ammonia and carbon dioxide, are recycled within the process.
- The process produces sodium carbonate, a valuable chemical, with calcium chloride as the only major by-product, which has some industrial uses.
Step 6: Answer Question 1(f) - Give two uses of sodium carbonate.
- f)
- Used in the manufacture of glass.
- Used for softening hard water.
- Used in the manufacture of detergents and soaps.
- Used in the paper industry.
Step 7: Answer Question 2(a) - What happens to the brightness of the bulb during electrolysis?
- a) The brightness of the bulb decreases. As electrolysis proceeds, the concentration of mobile ions (Cu2+ and Clβ) in the molten copper(II) chloride decreases as they are discharged at the electrodes. Fewer ions mean lower electrical conductivity, causing the bulb to dim.
Step 8: Answer Question 2(b) - Name suitable electrodes.
- b) A suitable pair of electrodes is graphite or platinum.
Step 9: Answer Question 2(c) - Identify the anode and cathode.
- c)
- Anode: The electrode connected to the positive terminal of the battery (left electrode in the diagram).
- Cathode: The electrode connected to the negative terminal of the battery (right electrode in the diagram).
Step 10: Answer Question 2(d) - Write the half equation for the reaction at the anode.
- d) At the anode, chloride ions are oxidized to chlorine gas.
2Clβ(l)βCl2β(g)+2eβ
Step 11: Answer Question 2(e) - State and explain one precaution.
- e)
- Wear safety goggles: Molten salts are very hot and corrosive; goggles protect eyes from splashes.
- Carry out in a fume cupboard: Chlorine gas is produced at the anode, which is toxic and should not be inhaled.
Step 12: Answer Question 3 - Explain the reactions of carbon(IV) oxide with sodium hydroxide and calcium hydroxide.
- When carbon(IV) oxide (CO2β) is bubbled through sodium hydroxide (NaOH), it reacts to form sodium carbonate (Na2βCO3β) and water. Both products are soluble in water, so no visible change is observed.
2NaOH(aq)+CO2β(g)βNa2βCO3β(aq)+H2βO(l)
- When CO2β is bubbled through calcium hydroxide (Ca(OH)2β, limewater), it reacts to form calcium carbonate (CaCO3β) and water. Calcium carbonate is insoluble in water, which causes a white precipitate to form, making the solution cloudy.
Ca(OH)2β(aq)+CO2β(g)βCaCO3β(s)+H2βO(l)
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