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(d) log⁡2log⁡e\text{(d) } \frac{\log 2}{\log e}

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یہاں آپ کے سوالات کے حل موجود ہیں:

Chapter #3

Question 22: log⁡e2\log_e 2 in common logarithm is written as

  1. لاگرتھم کی بیس تبدیل کرنے کا فارمولا استعمال کریں

    log⁡ba=log⁡calog⁡cb\log_b a = \frac{\log_c a}{\log_c b}۔ یہاں، a=2a=2, b=eb=e, اور ہم اسے کامن لاگرتھم (بیس 10) میں تبدیل کرنا چاہتے ہیں، لہذا c=10c=10۔

    log⁡e2=log⁡102log⁡10e\log_e 2 = \frac{\log_{10} 2}{\log_{10} e}
  2. کامن لاگرتھم میں، بیس 10 کو اکثر نہیں لکھا جاتا، لہذا log⁡10x\log_{10} x کو صرف log⁡x\log x لکھا جا سکتا ہے۔

    log⁡e2=log⁡2log⁡e\log_e 2 = \frac{\log 2}{\log e}

    The final answer is (d) log⁡2log⁡e\text{(d) } \frac{\log 2}{\log e}

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