We read your photo as:

Evaluate each trigonometric function.

Computer Science

ScanSolve AI Answer

Answer

−34-\frac{3}{4}

Step-by-step solution

3 steps
  1. Evaluate each trigonometric function.

    We need to find the values of sin⁡(2π3)\sin\left(\frac{2\pi}{3}\right), tan⁡(5π3)\tan\left(\frac{5\pi}{3}\right), cot⁡(−4π3)\cot\left(\frac{-4\pi}{3}\right), and cos⁡(5π6)\cos\left(\frac{5\pi}{6}\right).

    For sin⁡(2π3)\sin\left(\frac{2\pi}{3}\right):
    The angle 2π3\frac{2\pi}{3} is in the second quadrant.

    sin⁡(2π3)=sin⁡(π−π3)=sin⁡(π3)=32\sin\left(\frac{2\pi}{3}\right) = \sin\left(\pi - \frac{\pi}{3}\right) = \sin\left(\frac{\pi}{3}\right) = \frac{\sqrt{3}}{2}

    For tan⁡(5π3)\tan\left(\frac{5\pi}{3}\right):
    The angle 5π3\frac{5\pi}{3} is in the fourth quadrant.

    tan⁡(5π3)=tan⁡(2π−π3)=−tan⁡(π3)=−3\tan\left(\frac{5\pi}{3}\right) = \tan\left(2\pi - \frac{\pi}{3}\right) = -\tan\left(\frac{\pi}{3}\right) = -\sqrt{3}

    For cot⁡(−4π3)\cot\left(\frac{-4\pi}{3}\right):
    First, use the identity cot⁡(−x)=−cot⁡(x)\cot(-x) = -\cot(x):

    cot⁡(−4π3)=−cot⁡(4π3)\cot\left(\frac{-4\pi}{3}\right) = -\cot\left(\frac{4\pi}{3}\right)

    The angle 4π3\frac{4\pi}{3} is in the third quadrant.

    cot⁡(4π3)=cot⁡(π+π3)=cot⁡(π3)=13\cot\left(\frac{4\pi}{3}\right) = \cot\left(\pi + \frac{\pi}{3}\right) = \cot\left(\frac{\pi}{3}\right) = \frac{1}{\sqrt{3}}

    So,

    cot⁡(−4π3)=−13\cot\left(\frac{-4\pi}{3}\right) = -\frac{1}{\sqrt{3}}

    For cos⁡(5π6)\cos\left(\frac{5\pi}{6}\right):
    The angle 5π6\frac{5\pi}{6} is in the second quadrant.

    cos⁡(5π6)=cos⁡(π−π6)=−cos⁡(π6)=−32\cos\left(\frac{5\pi}{6}\right) = \cos\left(\pi - \frac{\pi}{6}\right) = -\cos\left(\frac{\pi}{6}\right) = -\frac{\sqrt{3}}{2}
  2. Substitute the values into the expression for AA.

    A=sin⁡(2π3)tan⁡(5π3)cot⁡(−4π3)cos⁡(5π6)A = \sin\left(\frac{2\pi}{3}\right) \tan\left(\frac{5\pi}{3}\right) \cot\left(\frac{-4\pi}{3}\right) \cos\left(\frac{5\pi}{6}\right) A=(32)⋅(−3)⋅(−13)⋅(−32)A = \left(\frac{\sqrt{3}}{2}\right) \cdot (-\sqrt{3}) \cdot \left(-\frac{1}{\sqrt{3}}\right) \cdot \left(-\frac{\sqrt{3}}{2}\right)
  3. Multiply the terms to simplify.

    A=32⋅(−31)⋅(−13)⋅(−32)A = \frac{\sqrt{3}}{2} \cdot \left(-\frac{\sqrt{3}}{1}\right) \cdot \left(-\frac{1}{\sqrt{3}}\right) \cdot \left(-\frac{\sqrt{3}}{2}\right)

    Multiply the numerators:

    3⋅(−3)⋅(−1)⋅(−3)=(−3)⋅(−1)⋅(−3)=3⋅(−3)=−33\sqrt{3} \cdot (-\sqrt{3}) \cdot (-1) \cdot (-\sqrt{3}) = (-3) \cdot (-1) \cdot (-\sqrt{3}) = 3 \cdot (-\sqrt{3}) = -3\sqrt{3}

    Multiply the denominators:

    2⋅1⋅3⋅2=432 \cdot 1 \cdot \sqrt{3} \cdot 2 = 4\sqrt{3}

    Combine the numerator and denominator:

    A=−3343A = \frac{-3\sqrt{3}}{4\sqrt{3}}

    Cancel out 3\sqrt{3} from the numerator and denominator:

    A=−34A = -\frac{3}{4}

    The simplified value is:

    −34-\frac{3}{4}
Was this helpful?

Try one yourself

A new problem that tests the same skill.

Still stuck on this one?

Ask a follow-up, and the answer starts from this question.

Got a different question?Ask your own question
Handwritten step-by-step solution preview

Handwritten Step-by-Step Solution

Get this as a handwritten image on WhatsApp — like a tutor wrote it for you.

Try on WhatsApp