Given the scalar function (x, y, z) = e^xy - x2yz2.
|Computer Science
Given the scalar function (x, y, z) = e^xy - x2yz2.
ScanSolve AI Answer
Answer
∇ϕ(x,y,z)=(yexy−2xyz2)i+(xexy−x2z2)j−2x2yzk
Given the scalar function ϕ(x,y,z)=exy−x2yz2.
The gradient of a scalar function ϕ(x,y,z) is given by:
∇ϕ=∂x∂ϕi+∂y∂ϕj+∂z∂ϕk
a) Evaluate ∇ϕ(x,y,z)
Step 1: Calculate the partial derivative with respect to x.
∂x∂ϕ=∂x∂(exy−x2yz2)=yexy−2xyz2
Step 2: Calculate the partial derivative with respect to y.
∂y∂ϕ=∂y∂(exy−x2yz2)=xexy−x2z2
Step 3: Calculate the partial derivative with respect to z.
∂z∂ϕ=∂z∂(exy−x2yz2)=−x2y(2z)=−2x2yz
Step 4: Combine the partial derivatives to form the gradient vector.
∇ϕ(x,y,z)=(yexy−2xyz2)i+(xexy−x2z2)j+(−2x2yz)k
The gradient is:
∇ϕ(x,y,z)=(yexy−2xyz2)i+(xexy−x2z2)j−2x2yzk
b) Evaluate ∇ϕ(2,−1,1)
Substitute x=2, y=−1, and z=1 into the expression for ∇ϕ(x,y,z) from part (a).
Step 1: Calculate the i component.
yexy−2xyz2=(−1)e(2)(−1)−2(2)(−1)(1)2=−e−2+4
Step 2: Calculate the j component.
xexy−x2z2=(2)e(2)(−1)−(2)2(1)2=2e−2−4
Step 3: Calculate the k component.
−2x2yz=−2(2)2(−1)(1)=−2(4)(−1)(1)=8
Step 4: Combine the components.
∇ϕ(2,−1,1)=(−e−2+4)i+(2e−2−4)j+8k
The gradient at (2,−1,1) is:
∇ϕ(2,−1,1)=(4−e−2)i+(2e−2−4)j+8k
c) Evaluate ∣∇ϕ(1,1,−1)∣
First, evaluate ∇ϕ(1,1,−1) by substituting x=1, y=1, and z=−1 into the expression for ∇ϕ(x,y,z).
Step 1: Calculate the i component.
yexy−2xyz2=(1)e(1)(1)−2(1)(1)(−1)2=e−2(1)(1)=e−2
Step 2: Calculate the j component.
xexy−x2z2=(1)e(1)(1)−(1)2(−1)2=e−1(1)=e−1
Step 3: Calculate the k component.
−2x2yz=−2(1)2(1)(−1)=−2(1)(−1)=2
Step 4: Form the gradient vector at (1,1,−1).
∇ϕ(1,1,−1)=(e−2)i+(e−1)j+2k
Step 5: Calculate the magnitude of the vector. The magnitude of a vector Ai+Bj+Ck is A2+B2+C2.
∣∇ϕ(1,1,−1)∣=(e−2)2+(e−1)2+(2)2∣∇ϕ(1,1,−1)∣=(e2−4e+4)+(e2−2e+1)+4∣∇ϕ(1,1,−1)∣=e2−4e+4+e2−2e+1+4∣∇ϕ(1,1,−1)∣=2e2−6e+9
The magnitude of the gradient at (1,1,−1) is:
∣∇ϕ(1,1,−1)∣=2e2−6e+9
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Given the scalar function (x, y, z) = e^xy - x^2yz^2. The gradient of a scalar function (x, y, z) is given by: = ( )/( x) i + ( )/( y) j + ( )/( z) k a) Evaluate (x, y, z) Step 1: Calculate the partial derivative with respect to x.
Given the scalar function (x, y, z) = e^xy - x2yz2.
This computer science problem involves algorithmic thinking and programming concepts. The solution below explains the approach, logic, and implementation step by step.
ScanSolve AI Answer
Given the scalar function (x, y, z) = e^xy - x^2yz^2. The gradient of a scalar function (x, y, z) is given by: = ( )/( x) i + ( )/( y) j + ( )/( z) k a) Evaluate (x, y, z) Step 1: Calculate the partial derivative with respect to x. ( )/( x) = ()/( x) (e^xy - x^2yz^2) = y e^xy - 2xyz^2 Step 2: Calculate the partial derivative with respect to y. ( )/( y) = ()/( y) (e^xy - x^2yz^2) = x e^xy - x^2z^2 Step 3: Calculate the partial derivative with respect to z. ( )/( z) = ()/( z) (e^xy - x^2yz^2) = -x^2y(2z) = -2x^2yz Step 4: Combine the partial derivatives to form the gradient vector. (x, y, z) = (y e^xy - 2xyz^2) i + (x e^xy - x^2z^2) j + (-2x^2yz) k The gradient is: (x, y, z) = (y e^xy - 2xyz^2) i + (x e^xy - x^2z^2) j - 2x^2yz k b) Evaluate (2, -1, 1) Substitute x=2, y=-1, and z=1 into the expression for (x, y, z) from part (a). Step 1: Calculate the i component. y e^xy - 2xyz^2 = (-1) e^(2)(-1) - 2(2)(-1)(1)^2 = -e^-2 + 4 Step 2: Calculate the j component. x e^xy - x^2z^2 = (2) e^(2)(-1) - (2)^2(1)^2 = 2e^-2 - 4 Step 3: Calculate the k component. -2x^2yz = -2(2)^2(-1)(1) = -2(4)(-1)(1) = 8 Step 4: Combine the components. (2, -1, 1) = (-e^-2 + 4) i + (2e^-2 - 4) j + 8 k The gradient at (2, -1, 1) is: (2, -1, 1) = (4 - e^-2) i + (2e^-2 - 4) j + 8 k c) Evaluate | (1, 1, -1)| First, evaluate (1, 1, -1) by substituting x=1, y=1, and z=-1 into the expression for (x, y, z). Step 1: Calculate the i component. y e^xy - 2xyz^2 = (1) e^(1)(1) - 2(1)(1)(-1)^2 = e - 2(1)(1) = e - 2 Step 2: Calculate the j component. x e^xy - x^2z^2 = (1) e^(1)(1) - (1)^2(-1)^2 = e - 1(1) = e - 1 Step 3: Calculate the k component. -2x^2yz = -2(1)^2(1)(-1) = -2(1)(-1) = 2 Step 4: Form the gradient vector at (1, 1, -1). (1, 1, -1) = (e - 2) i + (e - 1) j + 2 k Step 5: Calculate the magnitude of the vector. The magnitude of a vector Ai + Bj + Ck is sqrt(A^2 + B^2 + C^2). | (1, 1, -1)| = sqrt((e-2)^2 + (e-1)^2 + (2)^2) | (1, 1, -1)| = sqrt((e^2 - 4e + 4) + (e^2 - 2e + 1) + 4) | (1, 1, -1)| = sqrt(e^2 - 4e + 4 + e^2 - 2e + 1 + 4) | (1, 1, -1)| = sqrt(2e^2 - 6e + 9) The magnitude of the gradient at (1, 1, -1) is: | (1, 1, -1)| = sqrt(2e^2 - 6e + 9)