This computer science problem involves algorithmic thinking and programming concepts. The solution below explains the approach, logic, and implementation step by step.
In Kotlin, how do you declare a variable that cannot be reassigned after it is initialized?
Computer Science

ScanSolve AI Answer
በKotlin ውስጥ፣ ከተጀመረ በኋላ ዳግም ሊመደብ የማይችል ተለዋዋጭ (variable) ለመግለጽ፣ val ቁልፍ ቃል (keyword) ጥቅም ላይ ይውላል።
valተለዋዋጭ አንዴ ዋጋ ከተሰጠው በኋላ ሊቀየር እንደማይችል ያመለክታል።varተለዋዋጭ ደግሞ ዋጋው ሊቀየር የሚችል መሆኑን ያመለክታል።letለተግባራት ወሰን (scoping functions) የሚያገለግል ሲሆን ተለዋዋጭ ለመግለጽ አይደለም።constደግሞ በኮምፓይል ጊዜ (compile-time) ለሚታወቁ ቋሚዎች (constants) ብቻ የሚያገለግል ነው።
ስለዚህ ትክክለኛው አማራጭ val ነው።
- Using the
valkeyword
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Quick Answer
በKotlin ውስጥ፣ ከተጀመረ በኋላ ዳግም ሊመደብ የማይችል ተለዋዋጭ (variable) ለመግለጽ፣ val ቁልፍ ቃል (keyword) ጥቅም ላይ ይውላል። val ተለዋዋጭ አንዴ ዋጋ ከተሰጠው በኋላ ሊቀየር እንደማይችል ያመለክታል። var ተለዋዋጭ ደግሞ ዋጋው ሊቀየር የሚችል መሆኑን ያመለክታል። let ለተግባራት ወሰን (scoping functions) የሚያገለግል ሲሆን ተለዋዋጭ ለመግለጽ አይደለም።…
ScanSolve AI Answer
በKotlin ውስጥ፣ ከተጀመረ በኋላ ዳግም ሊመደብ የማይችል ተለዋዋጭ (variable) ለመግለጽ፣ val ቁልፍ ቃል (keyword) ጥቅም ላይ ይውላል። val ተለዋዋጭ አንዴ ዋጋ ከተሰጠው በኋላ ሊቀየር እንደማይችል ያመለክታል። var ተለዋዋጭ ደግሞ ዋጋው ሊቀየር የሚችል መሆኑን ያመለክታል። let ለተግባራት ወሰን (scoping functions) የሚያገለግል ሲሆን ተለዋዋጭ ለመግለጽ አይደለም። const ደግሞ በኮምፓይል ጊዜ (compile-time) ለሚታወቁ ቋሚዎች (constants) ብቻ የሚያገለግል ነው። ስለዚህ ትክክለኛው አማራጭ val ነው። Using the val keyword Send me the next one 📸