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Find the missing letter cluster based on the relationship between the given pairs: NICE : MOHJBDDF, KIND : JLHJMOCE, LAZY : ?
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The problem asks us to find the missing letter cluster based on the relationship between the given pairs.
Let's analyze the relationship between the first pair: NICE : MOHJBDDF
We can observe a pattern where each letter in the first word is replaced by two letters in the second cluster: the letter immediately preceding it and the letter immediately succeeding it in the alphabet.
- N (14) M (13), O (15)
- I (9) H (8), J (10)
- C (3) B (2), D (4)
- E (5) D (4), F (6)
So, NICE (N-1)(N+1)(I-1)(I+1)(C-1)(C+1)(E-1)(E+1) MOHJBDDF.
Let's verify this pattern with the second pair: KIND : JLHJMOCE
- K (11) J (10), L (12)
- I (9) H (8), J (10)
- N (14) M (13), O (15)
- D (4) C (3), E (5)
So, KIND (K-1)(K+1)(I-1)(I+1)(N-1)(N+1)(D-1)(D+1) JLHJMOCE.
The pattern holds true.
Now, let's apply this pattern to LAZY:
- L (12) K (11), M (13) KM
- A (1) Z (26), B (2) ZB (A-1 is Z, A+1 is B)
- Z (26) Y (25), A (1) YA (Z-1 is Y, Z+1 is A)
- Y (25) X (24), Z (26) XZ
Combining these, we get:
LAZY KM ZB YA XZ
Now, let's compare this with the given options:
- KMZBXAY
- MKBZAYZX
- AYZXMKBZ
- KMZBYAXZ
Our derived cluster matches option 4.
The final answer is
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