The primary function of DNA and RNA are __ and __ respectively.

Here are the solutions to the multiple-choice questions: 1. The primary function of DNA and RNA are ________ and ________ respectively. DNA's primary function is to store genetic information. RNA's primary function is involved in protein synthesis (making proteins). The correct option is A. A) Storing information, making proteins 2. If one of the DNA strand has the nucleotide sequence of 5'-CGA TTG CTA-3', what would be the nucleotide sequence of on the second strand? DNA strands are complementary and antiparallel. Adenine (A) pairs with Thymine (T), and Guanine (G) pairs with Cytosine (C). The complementary strand will run in the opposite direction. Given strand: 5'-CGA TTG CTA-3' Complementary bases: GCT AAC GAT Since the given strand is 5' to 3', the complementary strand will be 3' to 5'. Therefore, the sequence on the second strand is 3'-GCT AAC GAT-5'. The correct option is B. B) 3'-GCT AAC GAT-5' 3. During which step of cell division does crossing over occur? Crossing over, the exchange of genetic material between homologous chromosomes, is a crucial event that occurs during Prophase I of meiosis. The correct option is C. C) Prophase I 4. Assume that a homozygous black color (BB) is crossed with a homozygous white colour (bb). What is the probability that an offspring will have black color? Step 1: Identify the genotypes of the parents. Parent 1: Homozygous black (BB) Parent 2: Homozygous white (bb) Step 2: Determine the possible gametes from each parent. Parent 1 (BB) produces only B gametes. Parent 2 (bb) produces only b gametes. Step 3: Perform the cross to find the offspring genotypes. When BB is crossed with bb, all offspring will have the genotype Bb. Step 4: Determine the phenotype of the offspring. Since black color (B) is dominant over white color (b), all offspring with genotype Bb will express the black phenotype. Therefore, the probability that an offspring will have black color is 100\%. The correct option is C. C) 100 percent 5. Assuming that both parent plants in the diagram below are homozygous. Why would all of the f1 generation have yellow phenotypes? It is because: Step 1: Analyze the parent generation and F1 generation. The diagram shows a homozygous yellow pea seed crossed with a homozygous green pea seed (parent generation). All offspring in the F1 generation are yellow pea seeds. Step 2: Apply principles of Mendelian genetics. When two homozygous parents with contrasting traits are crossed, and all F1 offspring display only one of the parental traits, that trait is considered dominant. In this case, since all F1 offspring are yellow, yellow is the dominant trait. Step 3: Confirm with F2 generation (optional, but shown in diagram). The F2 generation shows a 3:1 ratio of yellow to green, which is characteristic of a monohybrid cross where the F1 generation (heterozygous) is self-crossed, further confirming that yellow is dominant. The reason all F1 generation have yellow phenotypes is because yellow is dominant over green. The correct option is B. B) Yellow is dominant over green That's 2 down. 3 left today — send the next one.