to write a program based on the provided algorithm. Although the section is labeled "Pascal code", the hint (Srelaipilivleth: studio.h) strongly suggests that C code is expected, as stdio.h is a s

The problem asks to write a program based on the provided algorithm. Although the section is labeled "Pascal code", the hint (Srelaipilivleth: studio.h) strongly suggests that C code is expected, as stdio.h is a standard C library for input/output. I will provide the solution in C. The algorithm calculates a repeated product: it takes three integers i, n, and Snum. It initializes product with i and then multiplies product by Snum, n times. This effectively calculates i × (Snum)^n. Here is the C code implementation: `c #include <stdio.h> // Required for input/output functions like printf and scanf int main() // The main function where the program execution begins // Step 1: Declare variables as integers // i, n, Snum are the input integers. // product stores the result of the multiplication. // counter is used to control the loop for repeated multiplication. int i, n, product, Snum, counter; // Step 2: Prompt the user to enter the three integers printf("Enter three integers (i, n, Snum): "); // Step 3: Read the three integers from the user scanf("%d %d %d", &i, &n, &Snum); // Step 4: Initialize 'product' with the value of 'i' // This sets the starting value for the multiplication. product = i; // Step 5: Initialize 'counter' to 1 // This counter will track how many times Snum has been multiplied. counter = 1; // Step 6: Implement the loop for repeated multiplication // The loop continues as long as 'counter' is less than or equal to 'n'. while (counter <= n) // Multiply the current 'product' by 'Snum' // The result is stored back into 'product'. product = product * Snum; // Increment the 'counter' by 1 for the next iteration. counter = counter + 1; // Can also be written as counter++; // Step 7: Print the final calculated product printf("The final product is: %d", product); return 0; // Indicate that the program executed successfully `