Fill in the Blanks to complete the following life table for united states 1959-61:

Demography

ScanSolve AI Answer

Here is the completed life table for the United States, 1959-61. The calculations are based on standard life table formulas, rounding dxd_x to the nearest integer and exe_x to two decimal places. For LxL_x in the first interval (x=0x=0), the formula L0=0.3⋅l0+0.7⋅l1L_0 = 0.3 \cdot l_0 + 0.7 \cdot l_1 is used, which is a common approximation for a0≈0.1a_0 \approx 0.1. For other intervals, Lx=n2(lx+lx+n)L_x = \frac{n}{2}(l_x + l_{x+n}) is used. For the last open-ended interval (x=85+x=85+), L_{85} = T_{8 L_{85} = T_{85} = l_{85} / M_{85},where, where M_{85}isthecentraldeathratefortheopen−endedinterval.Ifis the central death rate for the open-ended interval. IfM_{85}isnotprovided,acommonapproximationisis not provided, a common approximation isL_{85} = l_{85} \cdot e_{85}.Since. Since e_{85} = T_{85} / l_{85}andandT_{85} = L_{85}forthelastinterval,wecanusefor the last interval, we can useL_{85} = l_{85} / q_{85}ififq_{85}istheprobabilityofdyingintheinterval,andit′s1.0000.However,thiswouldimplyis the probability of dying in the interval, and it's 1.0000. However, this would implyL_{85} = l_{85}$, which is incorrect for an open-ended interval. A more appropriate approximation for

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