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What combination of goods maximizes the consumer's satisfaction?

Economics

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QuantityTotal Utility of BrowniesMarginal Utility of BrowniesMU/P for Brownies (PB=2P_B=2)Total Utility of CookiesMarginal Utility of CookiesMU/P for Cookies (PC=4P_C=4)Total Utility of Pieces of PieMarginal Utility of Pieces of PieMU/P for Pieces of Pie (PP=8P_P=8)
00--0--0--
1994.51616427273.375
2178433174.2551243
32473.54916475243
430636112399243
534426982109101.25
63621734111340.5
7360072-1-0.25110-3-0.375

a) What combination of goods maximizes the consumer's satisfaction?

  1. Calculate the Marginal Utility (MU) for each additional unit of each good.

    MU=ΔTU/ΔQMU = \Delta TU / \Delta Q. For example, for the 1st brownie, MUB=9−0=9MU_B = 9-0 = 9. For the 2nd brownie, MUB=17−9=8MU_B = 17-9 = 8.

  2. Calculate the Marginal Utility per Dollar (MU/P) for each unit of each good.

    MU/P=MU/PriceMU/P = MU / \text{Price}. Given prices are P_B = \2,, P_C = $4,, P_P = $8$.
    The table above shows these calculations.

  3. Allocate the budget of $40 by purchasing the good that offers the highest MU/P at each step, until the budget is exhausted.

    1. Budget: $40
      • Highest MU/P is 4.5 (1st Brownie). Buy 1 Brownie.
      • Cost: 2.RemainingBudget:2. Remaining Budget: 38.
    2. Budget: $38
      • Highest MU/P is 4.25 (2nd Cookies). Buy 1 Bag of Cookies.
      • Cost: 4.RemainingBudget:4. Remaining Budget: 34.
    3. Budget: $34
      • Highest MU/P is 4 (1st Cookies, 2nd Brownie). Let's buy 1st Cookies.
      • Cost: 4.RemainingBudget:4. Remaining Budget: 30. (Now 1 Brownie, 2 Cookies)
    4. Budget: $30
      • Highest MU/P is 4 (2nd Brownie, 3rd Cookies). Let's buy 2nd Brownie.
      • Cost: 2.RemainingBudget:2. Remaining Budget: 28. (Now 2 Brownies, 2 Cookies)
    5. Budget: $28
      • Highest MU/P is 4 (3rd Cookies). Buy 1 Bag of Cookies.
      • Cost: 4.RemainingBudget:4. Remaining Budget: 24. (Now 2 Brownies, 3 Cookies)
    6. Budget: $24
      • Highest MU/P is 3.5 (3rd Brownie). Buy 1 Brownie.
      • Cost: 2.RemainingBudget:2. Remaining Budget: 22. (Now 3 Brownies, 3 Cookies)
    7. Budget: $22
      • Highest MU/P is 3.375 (1st Pie). Buy 1 Piece of Pie.
      • Cost: 8.RemainingBudget:8. Remaining Budget: 14. (Now 3 Brownies, 3 Cookies, 1 Pie)
    8. Budget: $14
      • Highest MU/P is 3 (4th Brownie, 4th Cookies, 2nd Pie, 3rd Pie, 4th Pie). Let's pick 4th Brownie.
      • Cost: 2.RemainingBudget:2. Remaining Budget: 12. (Now 4 Brownies, 3 Cookies, 1 Pie)
    9. Budget: $12
      • Highest MU/P is 3 (4th Cookies, 2nd Pie, 3rd Pie, 4th Pie). Let's pick 4th Cookies.
      • Cost: 4.RemainingBudget:4. Remaining Budget: 8. (Now 4 Brownies, 4 Cookies, 1 Pie)
    10. Budget: $8
      • Highest MU/P is 3 (2nd Pie, 3rd Pie, 4th Pie). Let's pick 2nd Pie.
      • Cost: 8.RemainingBudget:8. Remaining Budget: 0. (Now 4 Brownies, 4 Cookies, 2 Pies)

    At this point, the budget is exhausted, and the MU/P for the last unit purchased of each good is 3.
    For 4th Brownie: MUB/PB=6/2=3MU_B/P_B = 6/2 = 3.
    For 4th Cookies: MUC/PC=12/4=3MU_C/P_C = 12/4 = 3.
    For 2nd Pie: MUP/PP=24/8=3MU_P/P_P = 24/8 = 3.
    The equimarginal principle is satisfied.

    The combination of goods that maximizes the consumer's satisfaction is:
    4 Brownies, 4 Bags of Cookies, and 2 Pieces of Pie\boxed{4 \text{ Brownies, } 4 \text{ Bags of Cookies, and } 2 \text{ Pieces of Pie}}.

    b) What is the total utility received from this combination?

  4. Sum the total utility for each good at the quantities determined in part (a).

    Total Utility from 4 Brownies (TUBTU_B at Q=4) = 30
    Total Utility from 4 Bags of Cookies (TUCTU_C at Q=4) = 61
    Total Utility from 2 Pieces of Pie (TUPTU_P at Q=2) = 51

  5. Calculate the total utility.

    Total Utility=TUB(4)+TUC(4)+TUP(2)=30+61+51=142\text{Total Utility} = TU_B(4) + TU_C(4) + TU_P(2) = 30 + 61 + 51 = 142

    The total utility received from this combination is 142\boxed{142}.

    c) If the price of pies fell to $6 a piece, what would be the new combination that would maximize the consumer's satisfaction?

  6. Recalculate MU/P for Pieces of Pie with the new price P_P = \6$.

    The MU for pie remains the same.

    QuantityMUPMU_PNew MUP/PPMU_P/P_P (PP=6P_P=6)
    1274.5
    2244
    3244
    4244
    5101.67
    640.67
    7-3-0.5
  7. Re-allocate the budget of $40 using the updated MU/P for pie.

    1. Budget: $40
      • Highest MU/P is 4.5 (1st Brownie, 1st Pie). Let's buy 1st Brownie.
      • Cost: 2.RemainingBudget:2. Remaining Budget: 38.
    2. Budget: $38
      • Highest MU/P is 4.5 (1st Pie). Buy 1 Piece of Pie.
      • Cost: 6.RemainingBudget:6. Remaining Budget: 32. (Now 1 Brownie, 1 Pie)
    3. Budget: $32
      • Highest MU/P is 4.25 (2nd Cookies). Buy 1 Bag of Cookies.
      • Cost: 4.RemainingBudget:4. Remaining Budget: 28. (Now 1 Brownie, 1 Cookies, 1 Pie)
    4. Budget: $28
      • Highest MU/P is 4 (1st Cookies, 2nd Brownie, 2nd Pie, 3rd Pie, 4th Pie). Let's buy 1st Cookies.
      • Cost: 4.RemainingBudget:4. Remaining Budget: 24. (Now 1 Brownie, 2 Cookies, 1 Pie)
    5. Budget: $24
      • Highest MU/P is 4 (2nd Brownie, 2nd Pie, 3rd Pie, 4th Pie). Let's buy 2nd Brownie.
      • Cost: 2.RemainingBudget:2. Remaining Budget: 22. (Now 2 Brownies, 2 Cookies, 1 Pie)
    6. Budget: $22
      • Highest MU/P is 4 (2nd Pie, 3rd Pie, 4th Pie, 3rd Cookies). Let's buy 2nd Pie.
      • Cost: 6.RemainingBudget:6. Remaining Budget: 16. (Now 2 Brownies, 2 Cookies, 2 Pies)
    7. Budget: $16
      • Highest MU/P is 4 (3rd Pie, 4th Pie, 3rd Cookies). Let's buy 3rd Pie.
      • Cost: 6.RemainingBudget:6. Remaining Budget: 10. (Now 2 Brownies, 2 Cookies, 3 Pies)
    8. Budget: $10
      • Highest MU/P is 4 (4th Pie, 3rd Cookies). Let's buy 4th Pie.
      • Cost: 6.RemainingBudget:6. Remaining Budget: 4. (Now 2 Brownies, 2 Cookies, 4 Pies)
    9. Budget: $4
      • Highest MU/P is 4 (3rd Cookies). Buy 1 Bag of Cookies.
      • Cost: 4.RemainingBudget:4. Remaining Budget: 0. (Now 2 Brownies, 3 Cookies, 4 Pies)

    At this point, the budget is exhausted.
    For 2nd Brownie: MUB/PB=8/2=4MU_B/P_B = 8/2 = 4.
    For 3rd Cookies: MUC/PC=16/4=4MU_C/P_C = 16/4 = 4.
    For 4th Pie: MUP/PP=24/6=4MU_P/P_P = 24/6 = 4.
    The equimarginal principle is satisfied.

    The new combination that maximizes the consumer's satisfaction is:
    2 Brownies, 3 Bags of Cookies, and 4 Pieces of Pie\boxed{2 \text{ Brownies, } 3 \text{ Bags of Cookies, and } 4 \text{ Pieces of Pie}}.

    That's 2 down. 3 left today — send the next one.Step 1: Calculate Marginal Utility (MU) and Marginal Utility per Dollar (MU/P) for each good.
    The prices are: Brownie (PBP_B) = 2,BagofCookies(2, Bag of Cookies (P_C)=) = 4, Piece of Pie (PPP_P) = 8.Thebudgetis8. The budget is 40.

    QuantityTUBTU_BMUBMU_BMUB/PBMU_B/P_BTUCTU_CMUCMU_CMUC/PCMU_C/P_CTUPTU_PMUPMU_PMUP/PPMU_P/P_P
    00--0--0--
    1994.51616427273.375
    2178433174.2551243
    32473.54916475243
    430636112399243
    534426982109101.25
    63621734111340.5
    7360072-1-0.25110-3-0.375

    a) What combination of goods maximizes the consumer's satisfaction?

  8. Allocate the 40budgetbychoosingthegoodwiththehighestMU/Pateachstep,ensuringtheequimarginalprinciple(40 budget by choosing the good with the highest MU/P at each step, ensuring the equimarginal principle (MU_B/P_B = MU_C/P_C = MU_P/P_P$) is met as closely as possible when the budget is exhausted.

    1. Buy 1st Brownie (MUB/PB=4.5MU_B/P_B = 4.5). Cost: 2.Budget:2. Budget: 38. (B=1)
    2. Buy 1st Bag of Cookies (MUC/PC=4.25MU_C/P_C = 4.25). Cost: 4.Budget:4. Budget: 34. (B=1, C=1)
    3. Buy 1st Piece of Pie (MUP/PP=3.375MU_P/P_P = 3.375). Cost: 8.Budget:8. Budget: 26. (B=1, C=1, P=1)
    4. Buy 2nd Brownie (MUB/PB=4MU_B/P_B = 4). Cost: 2.Budget:2. Budget: 24. (B=2, C=1, P=1)
    5. Buy 2nd Bag of Cookies (MUC/PC=4MU_C/P_C = 4). Cost: 4.Budget:4. Budget: 20. (B=2, C=2, P=1)
    6. Buy 3rd Bag of Cookies (MUC/PC=4MU_C/P_C = 4). Cost: 4.Budget:4. Budget: 16. (B=2, C=3, P=1)
    7. Buy 3rd Brownie (MUB/PB=3.5MU_B/P_B = 3.5). Cost: 2.Budget:2. Budget: 14. (B=3, C=3, P=1)
    8. Buy 2nd Piece of Pie (MUP/PP=3MU_P/P_P = 3). Cost: 8.Budget:8. Budget: 6. (B=3, C=3, P=2)
    9. Buy 4th Brownie (MUB/PB=3MU_B/P_B = 3). Cost: 2.Budget:2. Budget: 4. (B=4, C=3, P=2)
    10. Buy 4th Bag of Cookies (MUC/PC=3MU_C/P_C = 3). Cost: 4.Budget:4. Budget: 0. (B=4, C=4, P=2)

    The budget is exhausted, and the MU/P for the last unit of each good purchased is 3.

    The combination of goods that maximizes the consumer's satisfaction is 4 Brownies, 4 Bags of Cookies, and 2 Pieces of Pie\boxed{4 \text{ Brownies, } 4 \text{ Bags of Cookies, and } 2 \text{ Pieces of Pie}}.

    b) What is the total utility received from this combination?

  9. Sum the total utility for the quantities determined in part (a).

    Total Utility from 4 Brownies (TUBTU_B at Q=4) = 30
    Total Utility from 4 Bags of Cookies (TUCTU_C at Q=4) = 61
    Total Utility from 2 Pieces of Pie (TUPTU_P at Q=2) = 51

  10. Calculate the total utility.

    Total Utility=30+61+51=142\text{Total Utility} = 30 + 61 + 51 = 142

    The total utility received from this combination is 142\boxed{142}.

    c) If the price of pies fell to $6 a piece, what would be the new combination that would maximize the consumer's satisfaction?

  11. Recalculate the Marginal Utility per Dollar (MU/P) for Pieces of Pie with the new price P_P = \6$.

    The Marginal Utility (MU) values for pie remain the same as in the table from part (a).

    QuantityMUPMU_PNew MUP/PPMU_P/P_P (PP=6P_P=6)
    12727/6=4.527/6 = 4.5
    22424/6=424/6 = 4
    32424/6=424/6 = 4
    42424/6=424/6 = 4
    51010/6≈1.6710/6 \approx 1.67
    644/6≈0.674/6 \approx 0.67
    7-3−3/6=−0.5-3/6 = -0.5
  12. Re-allocate the budget of $40 by purchasing the good that offers the highest MU/P at each step, until the budget is exhausted, ensuring the equimarginal principle is met.

    (Refer to the MU/P values for brownies and cookies from the table in part (a), and the new MU/P values for pie above).

    1. Buy 1st Brownie (MUB/PB=4.5MU_B/P_B = 4.5). Cost: 2.RemainingBudget:2. Remaining Budget: 38. (Current: 1B)
    2. Buy 1st Piece of Pie (MUP/PP=4.5MU_P/P_P = 4.5). Cost: 6.RemainingBudget:6. Remaining Budget: 32. (Current: 1B, 1P)
    3. Buy 2nd Bag of Cookies (MUC/PC=4.25MU_C/P_C = 4.25). Cost: 4.RemainingBudget:4. Remaining Budget: 28. (Current: 1B, 1C, 1P)
    4. Buy 2nd Brownie (MUB/PB=4MU_B/P_B = 4). Cost: 2.RemainingBudget:2. Remaining Budget: 26. (Current: 2B, 1C, 1P)
    5. Buy 1st Bag of Cookies (MUC/PC=4MU_C/P_C = 4). Cost: 4.RemainingBudget:4. Remaining Budget: 22. (Current: 2B, 2C, 1P)
    6. Buy 2nd Piece of Pie (MUP/PP=4MU_P/P_P = 4). Cost: 6.RemainingBudget:6. Remaining Budget: 16. (Current: 2B, 2C, 2P)
    7. Buy 3rd Piece of Pie (MUP/PP=4MU_P/P_P = 4). Cost: 6.RemainingBudget:6. Remaining Budget: 10. (Current: 2B, 2C, 3P)
    8. Buy 4th Piece of Pie (MUP/PP=4MU_P/P_P = 4). Cost: 6.RemainingBudget:6. Remaining Budget: 4. (Current: 2B, 2C, 4P)
    9. Buy 3rd Bag of Cookies (MUC/PC=4MU_C/P_C = 4). Cost: 4.RemainingBudget:4. Remaining Budget: 0. (Current: 2B, 3C, 4P)

    At this point, the budget is exhausted. The MU/P for the last unit of each good purchased is 4 (MUB/PB=8/2=4MU_B/P_B = 8/2 = 4, MUC/PC=16/4=4MU_C/P_C = 16/4 = 4, MUP/PP=24/6=4MU_P/P_P = 24/6 = 4).

    The new combination that maximizes the consumer's satisfaction is 2 Brownies, 3 Bags of Cookies, and 4 Pieces of Pie\boxed{2 \text{ Brownies, } 3 \text{ Bags of Cookies, and } 4 \text{ Pieces of Pie}}.

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