Identify the principal amount (P), annual interest rate (R), and time (T).

P = \500$$R = 1.7% = \frac{1.7}{100} = 0.017$$T = 10$ years

$I = \$500 \times 0.017 \times 10$

$I = \$85$ The total interest earned is \boxed{\mathbf{\85}}$.

c) (ii)

P = \200$Daily interest rate$r_{daily} = 0.0035% = \frac{0.0035}{100} = 0.000035$
Number of days in 1 year = 365

$A = \$200(1 + 0.000035)^{365}$

$A = \$200(1.000035)^{365}$ $A \approx \$200 \times 1.012869$ $A \approx \$202.5738$ The value of Ollie's investment at the end of 1 year is \boxed{\mathbf{\202.57}}$.