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ScanSolve AI Answer
Here is the answer to question 1: 1. Be's 4th electron will have four quantum numbers Step 1: Determine the electronic configuration of Beryllium (Be). Beryllium has an atomic number of 4, meaning it has 4 electrons. The electronic configuration is 1s^2 2s^2. Step 2: Identify the 4th electron. The first two electrons are in the 1s orbital. The 3rd and 4th electrons are in the 2s orbital. Therefore, the 4th electron is the second electron in the 2s orbital. Step 3: Determine the quantum numbers for an electron in the 2s orbital. The principal quantum number (n) for the 2s orbital is 2. For an s orbital, the azimuthal quantum number (l) is 0. For l=0, the magnetic quantum number (m_l) can only be 0. Since it is the second electron in the 2s orbital, its spin quantum number (m_s) will be -1/2 (following Pauli's exclusion principle, where the first electron has +1/2 and the second has -1/2). Step 4: The four quantum numbers for Be's 4th electron are n=2, l=0, m_l=0, s=-1/2. Step 5: Compare these values with the given options. (a) n=1, l=0, m=0, s=+1/2 (b) n=1, l=1, m=+1, s=+1/2 (c) n=2, l=0, m=0, s=-1/2 (d) n=2, l=1, m=0, s=+1/2 The correct option is (c). The final answer is (c). That's 2 down. 3 left today — send the next one.