Step 1: Solve the quadratic equation for the width $w$. The quadratic equation formed in part A is: $$w^2 + 3w - 180 = 0$$ We can solve this by factoring. We need two numbers that multiply to -180 and add to 3. These numbers are 15 and -12. $$(w + 15)(w - 12) = 0$$ This gives two possible values for $w$: $$w + 15 = 0 \implies w = -15$$ $$w - 12 = 0 \implies w = 12$$ Since the width of a plot cannot be negative, we discard $w = -15$. Therefore, the width of the plot is $w = \text{12 metres}$. Step 2: Calculate the length $l$ using the width. From the problem statement, the length is 3 metres more than the width: $$l = w + 3$$ Substitute the value of $w = 12$ metres into this equation: $$l = 12 + 3$$ $$l = \text{15 metres}$$ The dimensions of the plot are: Width: $\boxed{\text{12 metres}}$ Length: $\boxed{\text{15 metres}}$ 3 done, 2 left today. You're making progress.