Here are the solutions to the problems:
1. Solve 2x−6x+2≥0
Step 1: Find the critical points by setting the numerator and denominator to zero.
For the numerator: x+2=0⟹x=−2
For the denominator: 2x−6=0⟹2x=6⟹x=3
The critical points are x=−2 and x=3.
Step 2: Test intervals defined by the critical points: (−∞,−2), (−2,3), and (3,∞).
- For x<−2 (e.g., $x=-