You're on a roll — let's solve this one. TASK (Bar Chart to Pie Chart) Step 1: Extract the number of supporters for each team from the bar chart. Team P: 10 supporters Team Q: 25 supporters Team R: 20 supporters Team S: 5 supporters Step 2: Calculate the total number of supporters. $$ \text{Total Supporters} = 10 + 25 + 20 + 5 = 60 $$ Step 3: Calculate the angle for each team in the pie chart. The full circle is $360^\circ$. Team P: $$ \text{Angle for P} = \frac{10}{60} \times 360^\circ = 60^\circ $$ Team Q: $$ \text{Angle for Q} = \frac{25}{60} \times 360^\circ = 150^\circ $$ Team R: $$ \text{Angle for R} = \frac{20}{60} \times 360^\circ = 120^\circ $$ Team S: $$ \text{Angle for S} = \frac{5}{60} \times 360^\circ = 30^\circ $$ Step 4: Calculate the percentage for each team (optional, but good for labeling). Team P: $$ \text{Percentage for P} = \frac{10}{60} \times 100\% \approx 16.67\% $$ Team Q: $$ \text{Percentage for Q} = \frac{25}{60} \times 100\% \approx 41.67\% $$ Team R: $$ \text{Percentage for R} = \frac{20}{60} \times 100\% \approx 33.33\% $$ Team S: $$ \text{Percentage for S} = \frac{5}{60} \times 100\% \approx 8.33\% $$ To represent this data on a pie chart: 1. Draw a circle. 2. Using a protractor, draw sectors with the calculated angles from the center of the circle. 3. Label each sector with the team name and its corresponding percentage or number of supporters. Item four (Circular Fence) Step 1: Identify the given information for the triangular land. Let the two given sides be $a = 550$ m and $b = 640$ m. The angle between them is $\gamma = 45^\circ$. The circular fence touches all three vertices, meaning it is the circumcircle of the triangle. Step 2: Calculate the length of the third side ($c$) using the Law of Cosines. The Law of Cosines states $c^2 = a^2 + b^2 - 2ab \cos \gamma$. $$ c^2 = (550)^2 + (640)^2 - 2(550)(640) \cos 45^\circ $$ $$ c^2 = 302500 + 409600 - 2(550)(640) \left(\frac{\sqrt{2}}{2}\right) $$ $$ c^2 = 712100 - 704000 \left(\frac{\sqrt{2}}{2}\right) $$ $$ c^2 = 712100 - 352000 \sqrt{2} $$ $$ c^2 \approx 712100 - 352000 \times 1.41421356 $$ $$ c^2 \approx 712100 - 497706.67 $$ $$ c^2 \approx 214393.33 $$ $$ c = \sqrt{214393.33} $$ $$ c \approx 462.92 \text{ m} $$ Step 3: Calculate the diameter of the circular fence (circumcircle) using the Sine Rule. The Sine Rule states $\frac{c}{\sin \gamma} = 2R$, where $R$ is the circumradius and $2R$ is the diameter. $$ \text{Diameter} = \frac{c}{\sin \gamma} $$ $$ \text{Diameter} = \frac{462.918}{\sin 45^\circ} $$ $$ \text{Diameter} = \frac{462.918}{\frac{\sqrt{2}}{2}} $$ $$ \text{Diameter} = \frac{462.918}{0.70710678} $$ $$ \text{Diameter} \approx 654.65 \text{ m} $$ The diameter of the circular fence is $\boxed{\text{654.65 m}}$. Step 4: Calculate the radius of the circular fence. $$ R = \frac{\text{Diameter}}{2} = \frac{654.65}{2} $$ $$ R \approx 327.33 \text{ m} $$ Step 5: Determine the area of the circular fence. The area of a circle is $A = \pi R^2$. $$ A = \pi (327.325)^2 $$ $$ A = \pi (107141.6) $$ $$ A \approx 3.14159 \times 107141.6 $$ $$ A \approx 336569.70 \text{ m}^2 $$ The area of the circular fence is $\boxed{\text{336569.70 m}^2}$. To draw an accurate diagram: 1. Draw a line segment, representing side $a = 550$ m, to scale (e.g., 5.5 cm). 2. At one end of this segment, use a protractor to draw an angle of $45^\circ$. 3. Along the ray of the $45^\circ$ angle, measure and mark a point representing side $b = 640$ m, to the same scale (e.g., 6.4 cm). 4. Connect the ends of the two scaled sides to complete the triangle. 5. To find the center of the circular fence (circumcenter), construct the perpendicular bisectors of any two sides of the triangle. The point where they intersect is the circumcenter. 6. Place the compass point at the circumcenter and extend the pencil to any vertex of the triangle. Draw the circle. This is the circular fence. 7. Measure the diameter of this drawn circle (to scale) to verify your calculated diameter. What's next?