I need this chemistry answers in English

• Process 1: Addition Polymerization. Reagents: Initiator (e.g., peroxide) or Ziegler-Natta catalyst. Conditions: High pressure, high temperature.
• Process 2: Complete Combustion. Reagents: Excess Oxygen. Conditions: Ignition/Heat.
• Process 3: Dehydration. Reagents: Concentrated sulfuric acid ($H_2SO_4$) or aluminum oxide ($Al_2O_3$). Conditions: Heat (e.g., $170^\circ C$ for $H_2SO_4$, $300-400^\circ C$ for $Al_2O_3$).
• Process 4: Esterification. Reagents: Propanoic acid ($CH_3CH_2COOH$), concentrated sulfuric acid ($H_2SO_4$) as catalyst. Conditions: Heat (reflux).
• Process 5: Hydrolysis. Reagents: Water, acid (e.g., $H_2SO_4$) or base (e.g., $NaOH$). Conditions: Heat (reflux).
• Process 6: Hydroxylation/Oxidation. Reagents: Cold, dilute, alkaline potassium permanganate(VII) ($KMnO_4$) (Baeyer's reagent). Conditions: Room temperature.
• Process 7: Condensation Polymerization. Reagents: Terephthalic acid (benzene-1,4-dicarboxylic acid). Conditions: Heat, catalyst. (Assuming it refers to Terylene formation from Ethan-1,2-diol).
• Process 8: Fractional Distillation. Reagents: None. Conditions: Heating.
• Process 9: Hydrogenation. Reagents: Hydrogen gas ($H_2$). Conditions: Nickel or Platinum catalyst, heat.
• Process 10: Fermentation. Reagents: Yeast. Conditions: Anaerobic, $37^\circ C$. (Assuming Glucose to Ethanol, despite arrow direction).
• Process 11: Condensation. Reagents: Fructose. Conditions: Enzyme. (Assuming Glucose to Sucrose).
• Process 12: Condensation Polymerization. Reagents: Terephthalic acid (benzene-1,4-dicarboxylic acid). Conditions: Heat, catalyst.
• Process 13: Biochemical Conversion/Reduction. Reagents: Microorganisms, reducing agents. Conditions: Specific fermentation conditions.
• Process 14: Condensation Polymerization. Reagents: Hexamethylenediamine (hexane-1,6-diamine). Conditions: Heat, high pressure.

• E: $C_2H_4$ (Ethene)
• F: $C_2H_2$ (Ethyne)
• G: $CO_2$ (Carbon dioxide)
• H: $H_2O$ (Water)
• M: $CH_3CH_2ONa$ (Sodium ethoxide)
• N: $CH_3COONa$ (Sodium ethanoate)
• P: $CH_4$ (Methane)
• R: $H_2$ (Hydrogen)
• S: $CO$ (Carbon monoxide)
• Q: $CH_3CH_2COOH$ (Propanoic acid)
• X: $CH_3CH_2OH$ (Ethanol)

• Reaction I: Addition Polymerization. Reagents: Initiator (e.g., peroxide) or Ziegler-Natta catalyst. Conditions: High pressure, high temperature.
• Reaction II: Hydration. Reagents: Steam ($H_2O(g)$), concentrated phosphoric acid ($H_3PO_4$) as catalyst. Conditions: High temperature (e.g., $300^\circ C$), high pressure (e.g., $60-70 \text{ atm}$).
• Reaction III: Oxidation. Reagents: Acidified potassium dichromate(VI) ($K_2Cr_2O_7/H^+$) or acidified potassium permanganate(VII) ($KMnO_4/H^+$). Conditions: Heat (reflux).
• Reaction IV: Free Radical Substitution (Halogenation). Reagents: Bromine ($Br_2$). Conditions: UV light (excess $Br_2$ for hexabromoethane).
• Reaction V: Addition (Halogenation). Reagents: Bromine ($Br_2$). Conditions: Room temperature, in an inert solvent (e.g., $CCl_4$) or aqueous.
• Reaction VI: Addition (Hydrohalogenation). Reagents: Hydrogen bromide ($HBr$). Conditions: Room temperature.
• Reaction VII: Decarboxylation. Reagents: Soda lime ($NaOH + CaO$). Conditions: Heat.
• Reaction VIII: Neutralization. Reagents: Sodium hydroxide ($NaOH$). Conditions: Room temperature.

Here are the differences

• Reaction IV: This is a free radical substitution reaction involving an alkane (ethane). It requires UV light and replaces hydrogen atoms with bromine atoms.
• Reaction V: This is an electrophilic addition reaction involving an alkene (ethene). It occurs at room temperature and adds bromine atoms across the double bond.

• Reaction VIII: This is a neutralization reaction between a carboxylic acid and a base, producing a salt and water.
• Process 4: This is an esterification reaction between an alcohol and a carboxylic acid, producing an ester and water.

• Reaction I: $nCH_2=CH_2 \xrightarrow{\text{High P, T, initiator}} -(CH_2-CH_2)_n-$
• Reaction II: $CH_2=CH_2(g) + H_2O(g) \xrightarrow{\text{Conc. H}_3PO_4, \text{High T, P}} CH_3CH_2OH(g)$
• Reaction III: $CH_3CH_2OH(aq) + 2[O] \xrightarrow{\text{K}_2Cr_2O_7/H^+, \text{Heat}} CH_3COOH(aq) + H_2O(l)$
• Reaction IV: $CH_3CH_3(g) + 6Br_2(g) \xrightarrow{UV \text{ light}} C_2Br_6(s) + 6HBr(g)$
• Reaction V: $CH_2=CH_2(g) + Br_2(aq) \xrightarrow{\text{Room temp}} CH_2Br-CH_2Br(aq)$
• Reaction VI: $CH_2=CH_2(g) + HBr(g) \xrightarrow{\text{Room temp}} CH_3CH_2Br(g)$
• Reaction VII: $CH_3COOH(s) + NaOH(s) \xrightarrow{\text{CaO, Heat}} CH_4(g) + Na_2CO_3(s)$
• Reaction VIII: $CH_3COOH(aq) + NaOH(aq) \xrightarrow{\text{Room temp}} CH_3COONa(aq) + H_2O(l)$
• Process 4: $CH_3CH_2OH(l) + CH_3CH_2COOH(l) \xrightarrow{\text{Conc. H}_2SO_4, \text{Heat}} CH_3CH_2COOCH_2CH_3(l) + H_2O(l)$
• Process 5: $CH_3CH_2COOCH_2CH_3(l) + H_2O(l) \xrightarrow{H^+ \text{ or } OH^-, \text{Heat}} CH_3CH_2COOH(l) + CH_3CH_2OH(l)$
• Process 6: $CH_2=CH_2(g) + H_2O(l) + [O] \xrightarrow{\text{Cold, dil. alk. KMnO}_4} HOCH_2-CH_2OH(aq)$
• Process 10: $C_6H_{12}O_6(aq) \xrightarrow{\text{Yeast, } 37^\circ C} 2CH_3CH_2OH(aq) + 2CO_2(g)$

Here's how to differentiate the compounds

• Physical Test: Boiling point. Methanol has a boiling point of $65^\circ C$, while pentan-1-ol has a boiling point of $138^\circ C$.
• Chemical Test: Esterification with ethanoic acid. Methanol forms methyl ethanoate (fruity smell), while pentan-1-ol forms pentyl ethanoate (banana-like smell).

• Physical Test: Solubility in water. Pentane is insoluble in water, whereas pentan-1-ol is sparingly soluble due to hydrogen bonding.
• Chemical Test: Reaction with sodium metal. Pentan-1-ol will react with sodium to produce hydrogen gas, while pentane will not react.

• Physical Test: Boiling point. Methanol has a boiling point of $65^\circ C$, while methanoic acid has a boiling point of $101^\circ C$.
• Chemical Test: Reaction with sodium carbonate/bicarbonate. Methanoic acid will react with sodium carbonate to produce carbon dioxide gas (effervescence), while methanol will not.

• Physical Test: State at room temperature. Propane is a gas at room temperature, while hexane is a liquid.
• Chemical Test: Both are alkanes and are generally unreactive with common laboratory reagents. There is no simple qualitative chemical test to differentiate them.

• Physical Test: Boiling point. Ethane has a boiling point of $-89^\circ C$, while ethene has a boiling point of $-104^\circ C$.
• Chemical Test: Reaction with bromine water. Ethene (an alkene) will decolorize orange/brown bromine water, while ethane (an alkane) will not react in the dark.

• Physical Test: State at room temperature. Ethanol is a liquid, while ethene is a gas.
• Chemical Test: Reaction with sodium metal. Ethanol will react with sodium to produce hydrogen gas, while ethene will not react.

The type of reaction leading to the formation of gas P (Methane) from Ethanoic acid is *Decarboxylation

The equation is:

j) The molecular formula of compound $-(CH_2CH_2)_n-$ is 3556.