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Answer

7

g−1(x)=x+1g^{-1}(x) = x+1

fg(x)=2x+1fg(x) = 2x+1

Step-by-step solution

3 steps

Here are the steps to solve the given problem:

We are given the following functions:

F(x)=2x+3F(x) = 2x+3 g(x)=x−1g(x) = x-1

We need to find F(2)F(2), g−1(x)g^{-1}(x), and fg(x)fg(x).

  1. Calculate F(2)F(2)

    To find F(2)F(2), we substitute x=2x=2 into the expression for F(x)F(x).

    F(2)=2(2)+3F(2) = 2(2) + 3 F(2)=4+3F(2) = 4 + 3 F(2)=7F(2) = 7

    The value of F(2)F(2) is 7\boxed{7}.

  2. Find g−1(x)g^{-1}(x)

    To find the inverse function g−1(x)g^{-1}(x), we set y=g(x)y = g(x), then swap xx and yy and solve for yy.
    Let y=x−1y = x-1.
    Swap xx and yy:

    x=y−1x = y-1

    Now, solve for yy:

    y=x+1y = x+1

    So, the inverse function is g−1(x)=x+1g^{-1}(x) = x+1.
    The inverse function of g(x)g(x) is g−1(x)=x+1\boxed{g^{-1}(x) = x+1}.

  3. Find fg(x)fg(x)

    The notation fg(x)fg(x) represents the composition of functions F(g(x))F(g(x)). We substitute the expression for g(x)g(x) into F(x)F(x).

    fg(x)=F(g(x))fg(x) = F(g(x))

    We know that g(x)=x−1g(x) = x-1.

    fg(x)=F(x−1)fg(x) = F(x-1)

    Now, we substitute (x−1)(x-1) in place of xx in the expression for F(x)=2x+3F(x) = 2x+3:

    fg(x)=2(x−1)+3fg(x) = 2(x-1) + 3 fg(x)=2x−2+3fg(x) = 2x - 2 + 3 fg(x)=2x+1fg(x) = 2x + 1

    The composite function fg(x)fg(x) is fg(x)=2x+1\boxed{fg(x) = 2x+1}.

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