We read your photo as:

Solve it in English No mistakes

English

ScanSolve AI Answer

Step-by-step solution

3 steps

To show that a matrix M is invertible, we need to demonstrate that its determinant is non-zero.

  1. Identify the given matrix.

    The matrix M is given as:

    M=[745−3]M = \begin{bmatrix} 7 & 4 \\ 5 & -3 \end{bmatrix}
  2. Calculate the determinant of the matrix M.

    For a 2×22 \times 2 matrix [abcd]\begin{bmatrix} a & b \\ c & d \end{bmatrix}, the determinant is calculated as ad−bcad - bc.
    For matrix M, we have a=7a=7, b=4b=4, c=5c=5, and d=−3d=-3.

    det⁡(M)=(7)(−3)−(4)(5)\det(M) = (7)(-3) - (4)(5) det⁡(M)=−21−20\det(M) = -21 - 20 det⁡(M)=−41\det(M) = -41
  3. Conclude whether the matrix is invertible.

    Since the determinant of M is −41-41, which is not equal to zero (det⁡(M)≠0\det(M) \neq 0), the matrix M is invertible.

    Since det⁡(M)=−41≠0, the matrix M is invertible.\boxed{\text{Since } \det(M) = -41 \neq 0, \text{ the matrix M is invertible.}}
Was this helpful?

Still stuck on this one?

Ask a follow-up, and the answer starts from this question.

Got a different question?Ask your own question
Handwritten step-by-step solution preview

Handwritten Step-by-Step Solution

Get this as a handwritten image on WhatsApp — like a tutor wrote it for you.

Try on WhatsApp