This English question involves literary analysis, grammar, or writing skills. The detailed response below provides a well-structured answer with supporting evidence and clear explanations.
ScanSolve AI Answer
Here are the solutions to your questions: 1. Which of the following numbers are not perfect squares? Step 1: A perfect square number can only end with the digits 0, 1, 4, 5, 6, or 9. Numbers ending with 2, 3, 7, or 8 cannot be perfect squares. Step 2: Check the last digit of each given number: • (i) 2032 ends with 2. • (ii) 2048 ends with 8. • (iii) 1027 ends with 7. • (iv) 1089 ends with 9. Step 3: Based on the rule, numbers ending in 2, 8, or 7 are not perfect squares. Thus, 2032, 2048, and 1027 are not perfect squares. The number 1089 ends in 9, which means it could be a perfect square. Indeed, 33^2 = 1089. Step 4: The numbers that are not perfect squares are 2032, 2048, and 1027. (i) 2032, (ii) 2048, (iii) 1027 2. Which one of 64^2, 108^2, 292^2, 36^2 has the last digit 4? Step 1: To find the last digit of a square, we only need to square the last digit of the original number. Step 2: Determine the last digit for the square of each number: • For 64^2: The last digit of 64 is 4. 4^2 = 16. The last digit of 64^2 is 6. • For 108^2: The last digit of 108 is 8. 8^2 = 64. The last digit of 108^2 is 4. • For 292^2: The last digit of 292 is 2. 2^2 = 4. The last digit of 292^2 is 4. • For 36^2: The last digit of 36 is 6. 6^2 = 36. The last digit of 36^2 is 6. Step 3: The numbers whose squares have a last digit of 4 are 108^2 and 292^2. 108^2 and 292^2 That's 2 down. 3 left today — send the next one.