Can you use English please

Okay, I will switch to English. Here are the solutions to the questions. 8. Find the 8th term and the sum of the first 15 terms of the AP: -7, -4, -1, Step 1: Identify the first term (a) and the common difference (d). The first term is a = -7. The common difference is d = -4 - (-7) = -4 + 7 = 3. Step 2: Find the 8th term (T_8) using the formula T_n = a + (n-1)d. T_8 = -7 + (8-1)3 T_8 = -7 + (7)3 T_8 = -7 + 21 T_8 = 14 Step 3: Find the sum of the first 15 terms (S_15) using the formula S_n = (n)/(2)[2a + (n-1)d]. S_15 = (15)/(2)[2(-7) + (15-1)3] S_15 = (15)/(2)[-14 + (14)3] S_15 = (15)/(2)[-14 + 42] S_15 = (15)/(2)[28] S_15 = 15 × 14 S_15 = 210 The 8th term is 14 and the sum of the first 15 terms is 210. 9. An arc of a circle, with a radius of 10cm, subtends an angle of 80^ at the centre of the circle. Find the length of the arc. Step 1: Identify the radius (r) and the angle (). The radius r = 10 cm. The angle = 80^. Step 2: Use the formula for arc length L = ()/(360^) × 2 r. L = (80^)/(360^) × 2 × (22)/(7) × 10 L = (8)/(36) × 2 × (22)/(7) × 10 L = (2)/(9) × (440)/(7) L = (880)/(63) L ≈ 13.968 The length of the arc is approximately 13.97 cm. 10. In a trapezium with an area of 40 cm^2, the ratio of the lengths of the parallel sides is 2:3. Find the lengths of the parallel sides if they are separated by 5cm. Step 1: Identify the area (A), the ratio of parallel sides, and the height (h). The area A = 40 cm^2. The ratio of parallel sides a:b = 2:3. The height h = 5 cm. Step 2: Let the parallel sides be 2x and 3x. Use the formula for the area of a trapezium A = (1)/(2)(a+b)h. 40 = (1)/(2)(2x + 3x)5 40 = (1)/(2)(5x)5 40 = (25x)/(2) Step 3: Solve for x. 40 × 2 = 25x 80 = 25x x = (80)/(25) x = (16)/(5) x = 3.2 Step 4: Find the lengths of the parallel sides. The first side a = 2x = 2 × 3.2 = 6.4 cm. The second side b = 3x = 3 × 3.2 = 9.6 cm. The lengths of the parallel sides are 6.4 cm and 9.6 cm. That's 2 down. 3 left today — send the next one.