Yes plot it on a graph

To plot the electric field ($E$) against distance ($r$), you would set the horizontal axis (x-axis) for $r$ from $0.1 \, \text{m}$ to $1.0 \, \text{m}$ and the vertical axis (y-axis) for $E$ from 0 to approximately $9 \times 10^5 \, \text{N C}^{-1}$. The graph would show a steep, downward-sloping curve. This curve represents an inverse square relationship ($E \propto \frac{1}{r^2}$), meaning $E$ decreases very rapidly as $r$ increases, especially at smaller distances, and then flattens out as $r$ gets larger.

To plot the electric potential ($V$) against distance ($r$), you would use the same horizontal axis for $r$ from $0.1 \, \text{m}$ to $1.0 \, \text{m}$. The vertical axis for $V$ would range from 0 to approximately $9 \times 10^4 \, \text{V}$. This graph would also be a downward-sloping curve, but it would be less steep than the $E$ vs. $r$ graph. This curve represents an inverse relationship ($V \propto \frac{1}{r}$), showing that $V$ decreases as $r$ increases, but at a slower rate compared to the electric field.

Both graphs would start at high values for small $r$ and decrease towards zero as $r$ increases, reflecting the inverse relationships with distance. The $E$ vs. $r$ graph would be steeper due to its inverse square dependence, while the $V$ vs. $r$ graph would be less steep due to its inverse dependence.