8.Thebulkmodulusofamaterialismostrelevantwhenanalyzing: 12.Intheequationforthermalstress,sigma=Y(alpha)(Delta)T,thetermalpharepresents: C.3.75x10⁶N 11.AbonewithYoung'smodulus1.50x10¹⁰N/m²hasaminimumeffective D.Specificheatcapacity 9.Asteelcableofdiameter1mmcansupportatensionof0.2kN.What C.10mm B.3.75x10⁵N D.14.14mm 13.AwireoflengthLandcross-sectonalareaAisstretchedtotwiceits C.Thermalconductivity 10.Theshearmodulusofamaterialrelatesto: A.Coeffcientoffriction D.3.75x10³N A.Awireundertension C.Arodbeingtwistedaboutitsaxis A.3.75x10⁴N B.7.07mm causesfracture,whatisthemaximumforcethebonecanwithstand? diameterof2.50cm²cross-sectionalarea.Ifaforceexceedingthis D.Thermalexpansionunderheating D.Abeamsupportedatbothendswithacentralload stress? C.Changeinlengthundertension A.5mm A.Changeinvolumeunderpressure B.Coeffcientoflinearexpansion B.Changeinshapewithoutchangeinvolume B.Asolidcubeunderuniformpressurefromallsides minimumdiameterisneededtosupport20kNwithoutexceedingthesame originallength.Thetruestresscomparedtoengineeringstressi

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Question 8: The bulk modulus of a material is most relevant when analyzing:

The bulk modulus measures a material's resistance to compression under uniform pressure.

  • A. A wire under tension (relates to Young's modulus)
  • B. A solid cube under uniform pressure from all sides (relates to bulk modulus)
  • C. A rod being twisted about its axis (relates to shear modulus)
  • D. A beam supported at both ends with a central load (relates to Young's modulus and shear modulus)

The correct option is B.
B. A solid cube under uniform pressure from all sides\boxed{\text{B. A solid cube under uniform pressure from all sides}}

Question 12: In the equation for thermal stress, σ=YαΔT\sigma = Y \alpha \Delta T, the term α\alpha represents:

The equation for thermal stress relates stress (σ\sigma) to Young's modulus (YY), the change in temperature (ΔT\Delta T), and the material's coefficient of thermal expansion (α\alpha).

  • A. Coefficient of friction
  • B. Coefficient of linear expansion
  • C. Thermal conductivity
  • D. Specific heat capacity

The correct option is B.
B. Coefficient of linear expansion\boxed{\text{B. Coefficient of linear expansion}}

Question 11: A bone with Young's modulus 1.50×1010 N/m21.50 \times 10^{10} \text{ N/m}^2 has a minimum effective cross-sectional area of 2.50 cm22.50 \text{ cm}^2. If a force exceeding this causes fracture, what is the maximum force the bone can withstand?

Assumption: The Young's modulus given is intended to be used as the ultimate tensile strength (fracture stress) for the purpose of this problem, despite it being a measure of stiffness.

Step 1: Convert the cross-sectional area to square meters.

A=2.50 cm2=2.50×(10−2 m)2=2.50×10−4 m2A = 2.50 \text{ cm}^2 = 2.50 \times (10^{-2} \text{ m})^2 = 2.50 \times 10^{-4} \text{ m}^2

Step 2: Use the formula for stress, σ=FA\sigma = \frac{F}{A}, to find the maximum force FmaxF_{max}.

Fmax=σ×AF_{max} = \sigma \times A

Substitute the given values, using Young's modulus as the fracture stress.

Fmax=(1.50×1010 N/m2)×(2.50×10−4 m2)F_{max} = (1.50 \times 10^{10} \text{ N/m}^2) \times (2.50 \times 10^{-4} \text{ m}^2) Fmax=(1.50×2.50)×10(10−4) NF_{max} = (1.50 \times 2.50) \times 10^{(10-4)} \text{ N}
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