Towns A and B are on the equator. A is on longitude 30°W. The time at B is 17:05 when it is 14:05 at A. Find longitude X. A ship sailed east from A to B at 450 knots. Find the travel time.

Time at B = 17:05 hours
Time at A = 14:05 hours
Time difference = $17:05 - 14:05 = 3$ hours.

Since the time at B is later than the time at A, town B is to the east of town A.

The Earth rotates $360^\circ$ in 24 hours.
Therefore, 1 hour corresponds to $\frac{360^\circ}{24} = 15^\circ$ of longitude.
Longitude difference = $3 \text{ hours} \times 15^\circ/\text{hour} = 45^\circ$.

Town A is at $30^\circ$W. Town B is $45^\circ$ to the east of A.
Starting from $30^\circ$W, moving $30^\circ$ east brings us to the Prime Meridian ($0^\circ$).
We need to move an additional $45^\circ - 30^\circ = 15^\circ$ further east.
This means town B is at $15^\circ$E.
So, X = $15^\circ$E.

The longitude X is $\boxed{\text{15}^\circ\text{E}}$.

Town A is at $30^\circ$W. Town B is at $15^\circ$E.
The angular distance is the sum of their longitudes because they are on opposite sides of the Prime Meridian.
Angular distance = $30^\circ + 15^\circ = 45^\circ$.

On the equator, $1^\circ$ of longitude corresponds to 60 nautical miles.
Distance = $45^\circ \times 60 \text{ nautical miles/degree} = 2700 \text{ nautical miles}$.

Given speed = 450 knots (450 nautical miles/hour).
Time taken = $\frac{2700 \text{ nautical miles}}{450 \text{ nautical miles/hour}}$
Time taken = 6 hours.

The time it took the ship to travel from A to B is $\boxed{\text{6 hours}}$.