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Answer

C

4

Step-by-step solution

24 steps

Here are the solutions to the questions:

23. The value of x in the equation 2x−3=52x - 3 = 5 is

  1. Add 3 to both sides of the equation.

    2x−3+3=5+32x - 3 + 3 = 5 + 3 2x=82x = 8
  2. Divide both sides by 2.

    2x2=82\frac{2x}{2} = \frac{8}{2} x=4x = 4

    The correct option is C. 4.

    24. The value of x in the equation x2=16x^2 = 16 is

  3. Take the square root of both sides of the equation.

    x2=16\sqrt{x^2} = \sqrt{16} x=±4x = \pm 4

    The correct option is D. ±4\pm 4.

    25. The value of x in the equation 2x+3=3x−52x + 3 = 3x - 5 is

  4. Subtract $2x$ from both sides of the equation.

    2x+3−2x=3x−5−2x2x + 3 - 2x = 3x - 5 - 2x 3=x−53 = x - 5
  5. Add 5 to both sides of the equation.

    3+5=x−5+53 + 5 = x - 5 + 5 8=x8 = x

    The correct option is A. 8.

    26. The value of x in the inequality 2x−1<52x - 1 < 5 is

  6. Add 1 to both sides of the inequality.

    2x−1+1<5+12x - 1 + 1 < 5 + 1 2x<62x < 6
  7. Divide both sides by 2.

    2x2<62\frac{2x}{2} < \frac{6}{2} x<3x < 3

    The correct option is B. x<3x < 3.

    27. The solution to the simultaneous equations: x+y=5x + y = 5 and x−y=1x - y = 1 is

  8. Add the two equations together to eliminate yy.

    (x+y)+(x−y)=5+1(x + y) + (x - y) = 5 + 1 2x=62x = 6
  9. Solve for xx.

    x=62x = \frac{6}{2} x=3x = 3
  10. Substitute the value of xx into the first equation (x+y=5x + y = 5).

    3+y=53 + y = 5
  11. Solve for yy.

    y=5−3y = 5 - 3 y=2y = 2

    The solution is x=3,y=2x=3, y=2.
    The correct option is A. x=3,y=2x=3, y=2.

    28. The value of x in the sequence 1,3,5,x,91, 3, 5, x, 9 is

  12. Determine the common difference between consecutive terms.

    3−1=23 - 1 = 2 5−3=25 - 3 = 2

    This is an arithmetic sequence with a common difference d=2d=2.

  13. Find the value of xx by adding the common difference to the preceding term.

    x=5+2x = 5 + 2 x=7x = 7

    The correct option is B. 7.

    29. The 10th term of the sequence 2,4,6,8,…2, 4, 6, 8, \dots is

  14. Identify the first term (aa) and the common difference (dd).

    The first term a=2a = 2.
    The common difference d=4−2=2d = 4 - 2 = 2.

  15. Use the formula for the nn-th term of an arithmetic sequence, Tn=a+(n−1)dT_n = a + (n-1)d, with n=10n=10.

    T10=2+(10−1)2T_{10} = 2 + (10-1)2 T10=2+(9)2T_{10} = 2 + (9)2 T10=2+18T_{10} = 2 + 18 T10=20T_{10} = 20

    The correct option is C. 20.

    30. The sum of the first 10 terms of the sequence 2,4,6,8,…2, 4, 6, 8, \dots is

  16. Identify the first term (aa), the common difference (dd), and the number of terms (nn).

    From question 29, a=2a = 2, d=2d = 2, and n=10n = 10.

  17. Use the formula for the sum of the first nn terms of an arithmetic sequence, Sn=n2(2a+(n−1)d)S_n = \frac{n}{2}(2a + (n-1)d).

    S10=102(2(2)+(10−1)2)S_{10} = \frac{10}{2}(2(2) + (10-1)2) S10=5(4+(9)2)S_{10} = 5(4 + (9)2) S10=5(4+18)S_{10} = 5(4 + 18) S10=5(22)S_{10} = 5(22) S10=110S_{10} = 110

    The correct option is D. 110.

    31. The common ratio of the sequence 2,4,8,16,…2, 4, 8, 16, \dots is

  18. Calculate the ratio of any term to its preceding term.

    42=2\frac{4}{2} = 2 84=2\frac{8}{4} = 2 168=2\frac{16}{8} = 2

    The common ratio r=2r = 2.
    The correct option is A. 2.

    32. The 5th term of the sequence 2,4,8,16,…2, 4, 8, 16, \dots is

  19. Identify the first term (aa) and the common ratio (rr).

    The first term a=2a = 2.
    From question 31, the common ratio r=2r = 2.

  20. Use the formula for the nn-th term of a geometric sequence, Tn=arn−1T_n = ar^{n-1}, with n=5n=5.

    T5=2×25−1T_5 = 2 \times 2^{5-1} T5=2×24T_5 = 2 \times 2^4 T5=2×16T_5 = 2 \times 16 T5=32T_5 = 32

    The correct option is B. 32.

    33. The sum to infinity of the sequence 1,12,14,…1, \frac{1}{2}, \frac{1}{4}, \dots is

  21. Identify the first term (aa) and the common ratio (rr).

    The first term a=1a = 1.
    The common ratio r=1/21=12r = \frac{1/2}{1} = \frac{1}{2}.

  22. Use the formula for the sum to infinity of a geometric sequence, S∞=a1−rS_\infty = \frac{a}{1-r}, since ∣r∣<1|r| < 1.

    S∞=11−12S_\infty = \frac{1}{1 - \frac{1}{2}} S∞=112S_\infty = \frac{1}{\frac{1}{2}} S∞=1×2S_\infty = 1 \times 2 S∞=2S_\infty = 2

    The correct option is A. 2.

    34. The value of x in the equation log⁡2x=3\log_2 x = 3 is

  23. Convert the logarithmic equation to its equivalent exponential form.

    The definition of logarithm states that log⁡ba=c\log_b a = c is equivalent to bc=ab^c = a.
    Here, b=2b=2, a=xa=x, and c=3c=3.

    23=x2^3 = x
  24. Calculate the value of 232^3.

    x=2×2×2x = 2 \times 2 \times 2 x=8x = 8

    The correct option is D. 8.

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