I don't understand French Solve in English using Base units

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a) i) An equation is said to be dimensionally homogeneous if the dimensions of all terms on both sides of the equation are identical. This means that each term must have the same fundamental units (e.g., mass, length, time).
a) ii) To show that the equation $v^2 = u^2 + 2as$ is dimensionally homogeneous, we need to find the dimensions of each term using base units (Length L, Mass M, Time T).

Identify the dimensions of each variable.
- Velocity ( $v$ , $u$ ) has dimensions of length per unit time: $[\text{L T}^{-1}]$ .
- Acceleration ( $a$ ) has dimensions of length per unit time squared: $[\text{L T}^{-2}]$ .
- Displacement ( $s$ ) has dimensions of length: $[\text{L}]$ .
- The number 2 is a dimensionless constant.
Determine the dimensions of each term in the equation.
For the term $v^2$ :
$[v^2] = ([\text{L T}^{-1}])^2 = [\text{L}^2 \text{T}^{-2}]$
For the term $u^2$ :
$[u^2] = ([\text{L T}^{-1}])^2 = [\text{L}^2 \text{T}^{-2}]$
For the term $2as$ :
$[2as] = [a] \times [s] = [\text{L T}^{-2}] \times [\text{L}] = [\text{L}^2 \text{T}^{-2}]$
Compare the dimensions of all terms.
All terms ( $v^2$ , $u^2$ , and $2as$ ) have the same dimensions, which are $[\text{L}^2 \text{T}^{-2}]$ .

Since the dimensions of every term in the equation are identical, the equation $v^2 = u^2 + 2as$ is dimensionally homogeneous.

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