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Multiply by the conjugate.

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Answer

1+621 + \frac{\sqrt{6}}{2}

Step-by-step solution

4 steps

To rationalize the expression, we multiply the numerator and the denominator by the conjugate of the denominator. The conjugate of 52−235\sqrt{2} - 2\sqrt{3} is 52+235\sqrt{2} + 2\sqrt{3}.

  1. Multiply by the conjugate.

    22+3352−23×52+2352+23\frac{2\sqrt{2} + 3\sqrt{3}}{5\sqrt{2} - 2\sqrt{3}} \times \frac{5\sqrt{2} + 2\sqrt{3}}{5\sqrt{2} + 2\sqrt{3}}
  2. Expand the numerator and the denominator.

    For the numerator: (22+33)(52+23)(2\sqrt{2} + 3\sqrt{3})(5\sqrt{2} + 2\sqrt{3})

    (22)(52)+(22)(23)+(33)(52)+(33)(23)(2\sqrt{2})(5\sqrt{2}) + (2\sqrt{2})(2\sqrt{3}) + (3\sqrt{3})(5\sqrt{2}) + (3\sqrt{3})(2\sqrt{3}) 10(22)+4(23)+15(32)+6(33)10(\sqrt{2}\sqrt{2}) + 4(\sqrt{2}\sqrt{3}) + 15(\sqrt{3}\sqrt{2}) + 6(\sqrt{3}\sqrt{3}) 10(2)+46+156+6(3)10(2) + 4\sqrt{6} + 15\sqrt{6} + 6(3) 20+196+1820 + 19\sqrt{6} + 18 38+19638 + 19\sqrt{6}

    For the denominator: (52−23)(52+23)(5\sqrt{2} - 2\sqrt{3})(5\sqrt{2} + 2\sqrt{3})
    This is in the form (a−b)(a+b)=a2−b2(a-b)(a+b) = a^2 - b^2.

    (52)2−(23)2(5\sqrt{2})^2 - (2\sqrt{3})^2 (52×(2)2)−(22×(3)2)(5^2 \times (\sqrt{2})^2) - (2^2 \times (\sqrt{3})^2) (25×2)−(4×3)(25 \times 2) - (4 \times 3) 50−1250 - 12 3838
  3. Combine the simplified numerator and denominator.

    38+19638\frac{38 + 19\sqrt{6}}{38}
  4. Simplify the fraction by dividing each term in the numerator by the denominator.

    3838+19638\frac{38}{38} + \frac{19\sqrt{6}}{38} 1+621 + \frac{\sqrt{6}}{2}
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