Rationalise the denominator by multiplying the numerator and denominator by the conjugate of the denominator.

The conjugate of $2-\sqrt{3}$ is $2+\sqrt{3}$.

Numerator: $(2+\sqrt{3})(2+\sqrt{3}) = 2(2) + 2\sqrt{3} + 2\sqrt{3} + (\sqrt{3})^2 = 4 + 4\sqrt{3} + 3 = 7 + 4\sqrt{3}$
Denominator: $(2-\sqrt{3})(2+\sqrt{3}) = 2^2 - (\sqrt{3})^2 = 4 - 3 = 1$

The simplified expression is $\boxed{7 + 4\sqrt{3}}$.

Substitute the value of $\sqrt{3}$ into the simplified expression $7 + 4\sqrt{3}$.

The evaluated value is $\boxed{13.928}$.