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To simplify the expression, rationalize the denominator by multiplying the numerator and denominator by the conjugate of the denominator. The conjugate of sqrt(7) + sqrt(2) is $sqrt(7) - sqrt(2)

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Answer

7−25\frac{\sqrt{7} - \sqrt{2}}{5}

Step-by-step solution

4 steps
  1. To simplify the expression, rationalize the denominator by multiplying the numerator and denominator by the conjugate of the denominator.

    The conjugate of 7+2\sqrt{7} + \sqrt{2} is 7−2\sqrt{7} - \sqrt{2}.

    17+2×7−27−2\frac{1}{\sqrt{7} + \sqrt{2}} \times \frac{\sqrt{7} - \sqrt{2}}{\sqrt{7} - \sqrt{2}}
  2. Multiply the numerators.

    1×(7−2)=7−21 \times (\sqrt{7} - \sqrt{2}) = \sqrt{7} - \sqrt{2}
  3. Multiply the denominators using the difference of squares formula (a+b)(a−b)=a2−b2(a+b)(a-b) = a^2 - b^2.

    (7+2)(7−2)=(7)2−(2)2(\sqrt{7} + \sqrt{2})(\sqrt{7} - \sqrt{2}) = (\sqrt{7})^2 - (\sqrt{2})^2 =7−2= 7 - 2 =5= 5
  4. Combine the simplified numerator and denominator.

    7−25\frac{\sqrt{7} - \sqrt{2}}{5}
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