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1 The following geometric patterns. A Geometric shape pattern. The number of units used to form the pattern are 1, 4, 9, 16, 25. Identify the next number in the sequence.

Mathematics

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Here are the solutions to the pattern problems.

1.1.1 Sticks Pattern

a) Step 1: Observe the pattern of sticks.
The number of sticks for the first three patterns are 4, 7, 10.
This is an arithmetic sequence with a common difference d=7−4=3d = 7 - 4 = 3.

  1. Calculate the number of sticks for the next pattern.

    The next pattern (4th pattern) will have 10+3=1310 + 3 = 13 sticks.
    The number of sticks needed is 13 sticks\boxed{\text{13 sticks}}.

    b) The number of sticks increases by 3 for each additional square added to the pattern.

    c) Step 1: Complete the table using the common difference of 3.

    Pattern numberNumber of sticks1427310413516619722825\begin{array}{|c|c|} \hline \text{Pattern number} & \text{Number of sticks} \\ \hline 1 & 4 \\ 2 & 7 \\ 3 & 10 \\ 4 & 13 \\ 5 & 16 \\ 6 & 19 \\ 7 & 22 \\ 8 & 25 \\ \hline \end{array}

    d) Step 1: Identify the first term (aa) and common difference (dd).
    a=4a = 4, d=3d = 3.

  2. Use the formula for the nn-th term of an arithmetic sequence, Tn=a+(n−1)dT_n = a + (n-1)d.

    For the 18th pattern (n=18n=18):

    T18=4+(18−1)×3T_{18} = 4 + (18-1) \times 3
  3. Calculate the value.

    T18=4+17×3=4+51=55T_{18} = 4 + 17 \times 3 = 4 + 51 = 55

    The number of sticks needed for the 18th pattern is 55 sticks\boxed{\text{55 sticks}}.

    e) Step 1: Use the formula for the nn-th term of an arithmetic sequence, Tn=a+(n−1)dT_n = a + (n-1)d.
    Substitute a=4a=4 and d=3d=3.

    Tn=4+(n−1)×3T_n = 4 + (n-1) \times 3
  4. Simplify the expression.

    Tn=4+3n−3=3n+1T_n = 4 + 3n - 3 = 3n + 1

    The algebraic rule is Tn=3n+1\boxed{T_n = 3n + 1}.

    1.1.2 Geometric shape pattern

    a) Step 1: Analyze the pattern of dots.
    Pattern 1 has 4×4=164 \times 4 = 16 dots.
    Pattern 2 has 3×3=93 \times 3 = 9 dots.
    Pattern 3 has 2×2=42 \times 2 = 4 dots.
    Pattern 4 has 1×1=11 \times 1 = 1 dot.

  5. Determine the rule for the number of dots (TnT_n) in terms of the pattern number (nn).

    The side length of the square is 5−n5-n. So, Tn=(5−n)2T_n = (5-n)^2.

  6. Calculate the number of dots for the 8th term (n=8n=8).

    T8=(5−8)2T_8 = (5-8)^2
  7. Simplify the expression.

    T8=(−3)2=9T_8 = (-3)^2 = 9

    The number of dots in the 8th term is 9 dots\boxed{\text{9 dots}}.

    b) Step 1: Use the rule Tn=(5−n)2T_n = (5-n)^2 for the 10th term (n=10n=10).

    T10=(5−10)2T_{10} = (5-10)^2
  8. Simplify the expression.

    T10=(−5)2=25T_{10} = (-5)^2 = 25

    The 10th term of the pattern is 25 dots\boxed{\text{25 dots}}.

    c) Step 1: Based on the analysis in part (a), the algebraic rule is the square of (5−n)(5-n).
    The algebraic rule is Tn=(5−n)2\boxed{T_n = (5-n)^2}.

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