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1.1 Sihinu ifọ ti akọkọ ti ìsalẹ̀ (State the formula for the period of oscillation): Step 1.1: The period T of a simple pendulum undergoing small oscillations is given by T = 2 sqrt((l)/(g)) where l is the length of the string in meters (m) and g is the acceleration due to gravity in meters per second squared ( m/s^2 ). T = 2 sqrt((l)/(g)) 1.2 Nika ìyè g ní South Africa (Value of g in South Africa): Step 1.2: The acceleration due to gravity in South Africa is approximately g ≈ 9.8 \, m/s^2 9.8 \, m/s^2 1.3 Ṣe ìṣirò ìyè akọkọ fún pendulum tí ó ni gigùn 1 m (Calculate period for length 1 m): Step 1.3: Use the formula for the period: T = 2 sqrt((l)/(g)) Substitute l = 1 \, m and g = 9.8 \, m/s^2 : T = 2 sqrt((1)/(9.8)) Calculate the fraction: (1)/(9.8) ≈ 0.1020 Take the square root: sqrt(0.1020) ≈ 0.3194 Multiply by 2 (using ≈ 3.142 ): 2 × 3.142 × 0.3194 ≈ 6.284 × 0.3194 ≈ 2.01 \, s ≈ 2.0 \, s 2.0 \, s 1.4 Ìṣirò fún gigùn mìíràn (Assuming length 0.5 m as common follow-up; adjust if diagram specifies): Step 1.4: Use the formula T = 2 sqrt((l)/(g)) Substitute l = 0.5 \, m , g = 9.8 \, m/s^2 : T = 2 sqrt((0.5)/(9.8)) Calculate the fraction: (0.5)/(9.8) ≈ 0.05102 Take the square root: sqrt(0.05102) ≈ 0.2259 Multiply by 2 : 2 × 3.142 × 0.2259 ≈ 6.284 × 0.2259 ≈ 1.42 \, s 1.4 \, s