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4 partsStep-by-step solution
4 stepsPart 1.1· 1 step
Sihinu ifọ ti akọkọ ti ìsalẹ̀ (State the formula for the period of oscillation)
The period $ T $ of a simple pendulum undergoing small oscillations is given by
where is the length of the string in meters (m) and is the acceleration due to gravity in meters per second squared ().
T = 2\pi \sqrt{\dfrac{l}{g}}
Part 1.2
Nika ìyè g ní South Africa (Value of $ g $ in South Africa)
The acceleration due to gravity in South Africa is approximately
9.8 , m/s^2
Part 1.3
Ṣe ìṣirò ìyè akọkọ fún pendulum tí ó ni gigùn 1 m (Calculate period for length 1 m)
Use the formula for the period
Substitute and :
Calculate the fraction:
Take the square root:
Multiply by (using ):
2.0 , s
Part 1.4
Ìṣirò fún gigùn mìíràn (Assuming length 0.5 m as common follow-up; adjust if diagram specifies)
Use the formula
Substitute , :
Calculate the fraction:
Take the square root:
Multiply by :
1.4 , s
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