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10m+4n=14 5m + n/2 = 14

Mathematics

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Answer

m=4915,n=−143m = \frac{49}{15}, n = -\frac{14}{3}

Step-by-step solution

3 steps

let's solve this system of equations.

Given equations:

  1. 10m+4n=1410m + 4n = 14
  2. 5m+n2=145m + \frac{n}{2} = 14
  1. Multiply equation (2) by 2 to eliminate the fraction and make the coefficient of mm easier to work with.

    2(5m+n2)=2(14)2\left(5m + \frac{n}{2}\right) = 2(14) 10m+n=28(3)10m + n = 28 \quad (3)
  2. Subtract equation (3) from equation (1) to eliminate mm.

    (10m+4n)−(10m+n)=14−28(10m + 4n) - (10m + n) = 14 - 28 10m+4n−10m−n=−1410m + 4n - 10m - n = -14 3n=−143n = -14 n=−143n = -\frac{14}{3}
  3. Substitute the value of nn into equation (3) to solve for mm.

    10m+(−143)=2810m + \left(-\frac{14}{3}\right) = 28 10m−143=2810m - \frac{14}{3} = 28 10m=28+14310m = 28 + \frac{14}{3} 10m=28×33+14310m = \frac{28 \times 3}{3} + \frac{14}{3} 10m=843+14310m = \frac{84}{3} + \frac{14}{3} 10m=98310m = \frac{98}{3} m=983×10m = \frac{98}{3 \times 10} m=9830m = \frac{98}{30} m=4915m = \frac{49}{15}

    The solution is m=4915,n=−143m = \frac{49}{15}, n = -\frac{14}{3}.

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