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Define the term triangle.

Mathematics

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11. Define the term triangle.
A triangle is a polygon with three straight sides and three vertices. It is a closed two-dimensional shape whose interior angles sum to 180∘180^\circ.

12. Classify the following triangles with angles:

a) 60∘,60∘,60∘60^\circ, 60^\circ, 60^\circ: Equilateral triangle (all angles are equal, implying all sides are equal).

b) 70∘,40∘,70∘70^\circ, 40^\circ, 70^\circ: Isosceles triangle (two angles are equal, implying two sides are equal).

c) 40∘,72∘,68∘40^\circ, 72^\circ, 68^\circ: Scalene triangle (all angles are different, implying all sides are different).

13. Calculate both the perimeter and area for the following:

a)

  1. Calculate the perimeter.

    The sides of the triangle are 9 cm9 \text{ cm}, 12 cm12 \text{ cm}, and 15 cm15 \text{ cm}.

    Perimeter=9 cm+12 cm+15 cm\text{Perimeter} = 9 \text{ cm} + 12 \text{ cm} + 15 \text{ cm} Perimeter=36 cm\text{Perimeter} = \boxed{\text{}36 \text{ cm}\text{}}
  2. Calculate the area.

    The base is 15 cm15 \text{ cm} and the height is 6 cm6 \text{ cm}.

    Area=12×base×height\text{Area} = \frac{1}{2} \times \text{base} \times \text{height} Area=12×15 cm×6 cm\text{Area} = \frac{1}{2} \times 15 \text{ cm} \times 6 \text{ cm} Area=12×90 cm2\text{Area} = \frac{1}{2} \times 90 \text{ cm}^2 Area=45 cm2\text{Area} = \boxed{\text{}45 \text{ cm}^2\text{}}

    b)

  3. Calculate the area.

    The base is 7 cm7 \text{ cm} and the height is 4 cm4 \text{ cm}.

    Area=12×base×height\text{Area} = \frac{1}{2} \times \text{base} \times \text{height} Area=12×7 cm×4 cm\text{Area} = \frac{1}{2} \times 7 \text{ cm} \times 4 \text{ cm} Area=12×28 cm2\text{Area} = \frac{1}{2} \times 28 \text{ cm}^2 Area=14 cm2\text{Area} = \boxed{\text{}14 \text{ cm}^2\text{}}

    Note: The perimeter cannot be calculated without the length of the third side. The given side 2.5 cm2.5 \text{ cm} is one of the non-base sides.

    c)
    The given side lengths are 3 cm3 \text{ cm}, 3 cm3 \text{ cm}, and 8 cm8 \text{ cm}.
    According to the triangle inequality theorem, the sum of the lengths of any two sides of a triangle must be greater than the length of the third side.
    Here, 3 cm+3 cm=6 cm3 \text{ cm} + 3 \text{ cm} = 6 \text{ cm}.
    Since 6 cm<8 cm6 \text{ cm} < 8 \text{ cm}, a triangle cannot be formed with these dimensions.

    14. In the triangle below, angles at A and B are 55∘55^\circ and 115∘115^\circ respectively. Find the value of xx at C.

  4. Find the interior angle at B.

    The exterior angle at B is 115∘115^\circ. The interior angle at B and the exterior angle at B are supplementary (they add up to 180∘180^\circ).

    Interior Angle at B=180∘−115∘\text{Interior Angle at B} = 180^\circ - 115^\circ Interior Angle at B=65∘\text{Interior Angle at B} = 65^\circ
  5. Use the sum of angles in a triangle.

    The sum of the interior angles of a triangle is 180∘180^\circ.

    Angle A+Interior Angle B+Angle C=180∘\text{Angle A} + \text{Interior Angle B} + \text{Angle C} = 180^\circ 55∘+65∘+x=180∘55^\circ + 65^\circ + x = 180^\circ 120∘+x=180∘120^\circ + x = 180^\circ
  6. Solve for xx.

    x=180∘−120∘x = 180^\circ - 120^\circ x=60∘x = \boxed{\text{}60^\circ\text{}}
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