This mathematics problem involves applying core mathematical principles and formulas. Below you will find a complete step-by-step solution with detailed explanations for each step, helping you understand not just the answer but the method behind it.

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Answer
36 cm
Here are the solutions to the problems:
11. Define the term triangle. A triangle is a polygon with three straight sides and three vertices. It is a closed two-dimensional shape whose interior angles sum to .
12. Classify the following triangles with angles: a) : Equilateral triangle (all angles are equal, implying all sides are equal). b) : Isosceles triangle (two angles are equal, implying two sides are equal). c) : Scalene triangle (all angles are different, implying all sides are different).
13. Calculate both the perimeter and area for the following:
a) Step 1: Calculate the perimeter. The sides of the triangle are , , and .
Step 2: Calculate the area. The base is and the height is . Area = \text{*45 cm^2*}
b) Step 1: Calculate the area. The base is and the height is . Area = \text{*14 cm^2*} Note: The perimeter cannot be calculated without the length of the third side. The given side is one of the non-base sides.
c) The given side lengths are , , and . According to the triangle inequality theorem, the sum of the lengths of any two sides of a triangle must be greater than the length of the third side. Here, . Since , a triangle cannot be formed with these dimensions.
14. In the triangle below, angles at A and B are and respectively. Find the value of at C. Step 1: Find the interior angle at B. The exterior angle at B is . The interior angle at B and the exterior angle at B are supplementary (they add up to ).
Step 2: Use the sum of angles in a triangle. The sum of the interior angles of a triangle is .
Step 3: Solve for . x = \text{*60^\circ*}
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This mathematics problem involves applying core mathematical principles and formulas. Below you will find a complete step-by-step solution with detailed explanations for each step, helping you understand not just the answer but the method behind it.