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14 Simplify (2a)-4 x 3a2. log8 + log 4.

Mathematics

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Answers

2 parts
a

316a\frac{3}{16a}

b

log⁡32\log 32

Step-by-step solution

6 steps

Part a· 4 steps

  1. Apply the exponent rule (xy)n=xnyn(xy)^n = x^n y^n to the first term.

    (2a)−4×3a3=(2−4a−4)×3a3(2a)^{-4} \times 3a^3 = (2^{-4} a^{-4}) \times 3a^3
  2. Calculate 2−42^{-4} and combine the constant terms.

    124a−4×3a3=116a−4×3a3\frac{1}{2^4} a^{-4} \times 3a^3 = \frac{1}{16} a^{-4} \times 3a^3
  3. Multiply the terms with aa using the rule xm×xn=xm+nx^m \times x^n = x^{m+n}.

    316a−4+3=316a−1\frac{3}{16} a^{-4+3} = \frac{3}{16} a^{-1}
  4. Express a−1a^{-1} as 1a\frac{1}{a}.

    316a\frac{3}{16a}

    The simplified expression is:

    316a\boxed{\frac{3}{16a}}

Part b

log⁡32\log 32

  1. Apply the logarithm property log⁡x+log⁡y=log⁡(xy)\log x + \log y = \log (xy).

    log⁡8+log⁡4=log⁡(8×4)\log 8 + \log 4 = \log (8 \times 4)
  2. Perform the multiplication.

    log⁡32\log 32

    The simplified expression is:

    log⁡32\boxed{\log 32}
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