Write 17,208,304 in words and VMCMXLV in Arabic figures.

The number is 17,208,304.

• 17 is in the millions place.
• 208 is in the thousands place.
• 304 is in the hundreds, tens, and ones place.

• 17,000,000 is seventeen million.
• 208,000 is two hundred eight thousand.
• 304 is three hundred four.

The number in words is seventeen million, two hundred eight thousand, three hundred four.

The answer is:

• Seventeen million, two hundred eight thousand, three hundred four.

V M C M X L V

• V = 5
• M = 1000
• C = 100
• M = 1000
• X = 10
• L = 50
• V = 5

• VM: This is not a standard Roman numeral combination. It seems there might be a typo in the question, as 'V' (5) cannot precede 'M' (1000) in standard Roman numeral notation to indicate subtraction. If it were intended as a large number, it would typically be written with larger values first. Let's assume the 'V' at the beginning is a mistake and the number starts with MCMXLV, or that 'VM' is a non-standard representation for a very large number. Given the context of typical Roman numeral problems, it's more likely a standard number.

Let's re-evaluate the Roman numeral string: VMCMXLV.
If we interpret it strictly:
V = 5
M = 1000
CM = 900 (C before M means 1000 - 100)
XL = 40 (X before L means 50 - 10)
V = 5

If the 'V' at the beginning is a separate digit, it would be 5 + 1000 + 900 + 40 + 5 = 1950.
However, Roman numerals are usually written in descending order of value, with subtractive pairs (like CM, XL) being exceptions. A 'V' at the very beginning followed by 'M' is highly unusual.

Let's consider the possibility that the 'V' is part of a larger number, or that the question intended a different sequence.
If it was MCMXLV, the value would be $1000 + (1000 - 100) + (50 - 10) + 5 = 1000 + 900 + 40 + 5 = 1945$.

Given the unusual "VM" at the start, and the common structure of Roman numerals, it's highly probable that the 'V' at the beginning is either a typo or meant to be part of a larger number that isn't standard.
However, if we treat it as a sequence of individual Roman numerals and apply the rules:
V = 5
M = 1000
CM = 900
XL = 40
V = 5

If we assume the 'V' at the beginning is a separate value, and then the rest follows standard rules:
$5 + 1000 + (1000 - 100) + (50 - 10) + 5 = 5 + 1000 + 900 + 40 + 5 = 1950$.

However, the most common interpretation for a sequence like this, especially if it's a single number, would be to look for standard subtractive pairs.
MCMXLV:
M = 1000
CM = 900 (1000 - 100)
XL = 40 (50 - 10)
V = 5
Summing these: $1000 + 900 + 40 + 5 = 1945$.

The initial 'V' in "VMCMXLV" is problematic. If it's a typo and should be MCMXLV, the answer is 1945. If it's meant to be a very large number, it's not standard.
Assuming the most common interpretation of such a sequence, and that the 'V' at the beginning is a mistake or part of a larger, non-standard notation, I will proceed with the standard interpretation of MCMXLV. If "VM" was intended to be a number, it's not standard.

Let's assume the question meant MCMXLV.

M = 1000
C = 100
X = 10
L = 50
V = 5

• CM: C (100) before M (1000) means $1000 - 100 = 900$.
• XL: X (10) before L (50) means $50 - 10 = 40$.

$1000 + 900 + 40 + 5 = 1945$.

The answer is:

• 1945

The square root of a number $x$ is a number $y$ such that $y \times y = x$.

We are looking for $\sqrt{196}$.
We can test numbers:
$10 \times 10 = 100$
$12 \times 12 = 144$
$14 \times 14 = 196$

The square root of 196 is 14.

The answer is:

• 14

Start time: 8:00 am
Duration: 7 hours 30 minutes
Add 7 hours to 8:00 am: $8:00 \text{ am} + 7 \text{ hours} = 3:00 \text{ pm}$.

Add 30 minutes to 3:00 pm: $3:00 \text{ pm} + 30 \text{ minutes} = 3:30 \text{ pm}$.

The answer is:

• 3:30 pm

Let $B$ be the number of boys and $G$ be the number of girls.
Total pupils: $B + G = 59$
Boys are 7 more than girls: $B = G + 7$

$(G + 7) + G = 59$
$2G + 7 = 59$

$2G = 59 - 7$
$2G = 52$
$G = \frac{52}{2}$
$G = 26$

$B = G + 7$
$B = 26 + 7$
$B = 33$

The answer is:

• 33 boys

Fraction spent on biscuits = $\frac{1}{4}$.

Remaining fraction = $1 - \frac{1}{4} = \frac{4}{4} - \frac{1}{4} = \frac{3}{4}$.

Peter spent $\frac{1}{2}$ of the rest on bananas.
Fraction spent on bananas = $\frac{1}{2} \times \frac{3}{4} = \frac{3}{8}$.

Total fraction spent = Fraction on biscuits + Fraction on bananas
Total fraction spent = $\frac{1}{4} + \frac{3}{8}$
To add these, find a common denominator, which is 8.
$\frac{1}{4} = \frac{1 \times 2}{4 \times 2} = \frac{2}{8}$
Total fraction spent = $\frac{2}{8} + \frac{3}{8} = \frac{5}{8}$.

Fraction left = $1 - \text{Total fraction spent}$
Fraction left = $1 - \frac{5}{8} = \frac{8}{8} - \frac{5}{8} = \frac{3}{8}$.

The answer is:

• $\boxed{\frac{3}{8}}$

This is an inverse proportion problem: more students mean less time to complete the work.
Let $S_1 = 21$ students, $T_1 = 4$ hours.
Let $S_2$ be the unknown number of students, $T_2 = 3\frac{1}{2}$ hours $= 3.5$ hours.

$S_1 \times T_1 = S_2 \times T_2$

$21 \times 4 = S_2 \times 3.5$
$84 = 3.5 S_2$
$S_2 = \frac{84}{3.5}$
$S_2 = \frac{840}{35}$
$S_2 = 24$

The answer is:

• 24 students

Total eggs = 80
Bad eggs = 20
Good eggs = Total eggs - Bad eggs = $80 - 20 = 60$.

Fraction of good eggs = $\frac{\text{Number of good eggs}}{\text{Total eggs}} = \frac{60}{80}$.

Percentage of good eggs = $\frac{60}{80} \times 100\%$
Percentage of good eggs = $\frac{6}{8} \times 100\%$
Percentage of good eggs = $\frac{3}{4} \times 100\%$
Percentage of good eggs = $0.75 \times 100\%$
Percentage of good eggs = $75\%$.

The answer is:

• 75%

A square has four equal sides. The distance around a square plot is its perimeter.
Perimeter of a square = $4 \times \text{side}$.

Perimeter = 36 m
$4 \times \text{side} = 36 \text{ m}$
$\text{side} = \frac{36}{4} \text{ m}$
$\text{side} = 9 \text{ m}$.

Area of a square = $\text{side} \times \text{side}$
Area = $9 \text{ m} \times 9 \text{ m}$
Area = $81 \text{ m}^2$.

The answer is:

• $\boxed{81 \text{ m}^2}$