Solve 2/5 of (6(2)/(5)−1/2(1(2)/(3)+1/3)) × 1/5

Question

ScanSolve AI Tutor · Accepted Answer

Ili kutatua tatizo hili, tutafuata utaratibu wa shughuli (BODMAS/PEMDAS), tukianza na mabano ya ndani kabisa.

\frac{2}{5} \text{ of } \left(6\frac{2}{5} - \frac{1}{2}\left(1\frac{2}{3} + \frac{1}{3}\right) \times \frac{1}{5}\right)

Kumbuka kuwa "of" inamaanisha kuzidisha.

Tatua mabano ya ndani kabisa.
Kwanza, badilisha namba mchanganyiko kuwa sehemu isiyofaa: $1\frac{2}{3} = \frac{1 \times 3 + 2}{3} = \frac{5}{3}$ .
Sasa jumlisha sehemu ndani ya mabano:
$1\frac{2}{3} + \frac{1}{3} = \frac{5}{3} + \frac{1}{3} = \frac{6}{3} = 2$
Badilisha matokeo ya Step 1 kwenye usemi mkuu na ufanye kuzidisha ndani ya mabano makubwa.
$\frac{1}{2} \times 2 \times \frac{1}{5}$
Zidisha kutoka kushoto kwenda kulia:
$\frac{1}{2} \times 2 = 1$
Kisha:
$1 \times \frac{1}{5} = \frac{1}{5}$
Badilisha matokeo ya Step 2 kwenye mabano makubwa na ufanye kutoa.
Kwanza, badilisha namba mchanganyiko $6\frac{2}{5}$ kuwa sehemu isiyofaa: $6\frac{2}{5} = \frac{6 \times 5 + 2}{5} = \frac{30 + 2}{5} = \frac{32}{5}$ .
Sasa toa:
$\frac{32}{5} - \frac{1}{5} = \frac{31}{5}$
Hatimaye, zidisha matokeo ya Step 3 na $\frac{2}{5}$ .
$\frac{2}{5} \times \frac{31}{5}$
Zidisha namba za juu na namba za chini:
$\frac{2 \times 31}{5 \times 5} = \frac{62}{25}$
Badilisha sehemu isiyofaa kuwa namba mchanganyiko.
$\frac{62}{25} = 2\frac{12}{25}$
Jibu la mwisho ni:
$2\frac{12}{25}$

Solve (2)/(5) of (6(2)/(5)-(1)/(2)(1(2)/(3)+(1)/(3))) x (1)/(5)